Ris*_*ava 5 android preferenceactivity android-alertdialog edittextpreference
如何在edittextpreference对话框中设置null验证,这样如果它为null,则用户不应该单击ok,并且应该在对话框本身中显示一些消息.我一直试图找到它很长一段时间但没有成功......
edttxtpref = (EditTextPreference) getPreferenceScreen().findPreference(
"edttxtkey");
edttxtpref.setOnPreferenceChangeListener(new OnPreferenceChangeListener() {
@Override
public boolean onPreferenceChange(
android.preference.Preference preference, Object newValue) {
if (newValue.toString().trim().equals("")) {
Toast.makeText(getActivity(), "Username can not be empty",
Toast.LENGTH_LONG).show();
return false;
}
return true;
}
});
Run Code Online (Sandbox Code Playgroud)
这样就完成了验证,如果我们想在对话框本身中显示消息,那么就必须按照Phil已经告知的那样创建一个自定义对话框.
当 edittext 为空时,“确定”按钮将被禁用,一旦输入文本,它将被启用::
public class CustomEditTextPreference extends EditTextPreference implements
OnClickListener {
public CustomEditTextPreference(Context ctx, AttributeSet attrs, int defStyle)
{
super(ctx, attrs, defStyle);
}
public CustomEditTextPreference(Context ctx, AttributeSet attrs)
{
super(ctx, attrs);
}
private class EditTextWatcher implements TextWatcher
{
@Override
public void onTextChanged(CharSequence s, int start, int before, int count){}
@Override
public void beforeTextChanged(CharSequence s, int start, int before, int count){}
@Override
public void afterTextChanged(Editable s)
{
onEditTextChanged();
}
}
EditTextWatcher m_watcher = new EditTextWatcher();
/**
* Return true in order to enable positive button or false to disable it.
*/
protected boolean onCheckValue(String value)
{
if (value.trim().equals(""))
{
return false;
}
return true;
}
protected void onEditTextChanged()
{
boolean enable = onCheckValue(getEditText().getText().toString());
Dialog dlg = getDialog();
if(dlg instanceof AlertDialog)
{
AlertDialog alertDlg = (AlertDialog)dlg;
Button btn = alertDlg.getButton(AlertDialog.BUTTON_POSITIVE);
btn.setEnabled(enable);
}
}
@Override
protected void showDialog(Bundle state)
{
super.showDialog(state);
getEditText().removeTextChangedListener(m_watcher);
getEditText().addTextChangedListener(m_watcher);
onEditTextChanged();
}
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2381 次 |
| 最近记录: |