ntm*_*ntm 38 java null android calendar dayofweek
我试着通过这种方式得到一个带有实际工作日名称的字符串:
Calendar c = Calendar.getInstance();
int dayOfWeek = c.get(Calendar.DAY_OF_WEEK);
if (c.get(Calendar.MONDAY) == dayOfWeek) weekDay = "monday";
else if (c.get(Calendar.TUESDAY) == dayOfWeek) weekDay = "tuesday";
else if (c.get(Calendar.WEDNESDAY) == dayOfWeek) weekDay = "wednesday";
else if (c.get(Calendar.THURSDAY) == dayOfWeek) weekDay = "thursday";
else if (c.get(Calendar.FRIDAY) == dayOfWeek) weekDay = "friday";
else if (c.get(Calendar.SATURDAY) == dayOfWeek) weekDay = "saturday";
else if (c.get(Calendar.SUNDAY) == dayOfWeek) weekDay = "sunday";
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但weekDay保持总是为空,我实际上不知道为什么因为调试器说dayOfWeek是5所以我应该等于c.get(Calendar.THURSDAY)
san*_*one 78
就这么简单
sCalendar = Calendar.getInstance();
String dayLongName = sCalendar.getDisplayName(Calendar.DAY_OF_WEEK, Calendar.LONG, Locale.getDefault());
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小智 60
我通过以下方式完成了这项工作:
String weekDay;
SimpleDateFormat dayFormat = new SimpleDateFormat("EEEE", Locale.US);
Calendar calendar = Calendar.getInstance();
weekDay = dayFormat.format(calendar.getTime());
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您需要查看SimpleDateFormat以了解更多信息.我认为这是最干净的方法,因为你只需要获取字符串值就不需要switch或if语句.
小智 16
您应该将dayOfWeek直接与Calendar.MONDAY等进行比较.请参阅下面的代码
另外,如果是其他的话,我已将括号括起来.不要依赖缩进代码流,即使你的if-else只有一个语句,也要明确地加上括号.
public static void main(String[] args) {
String weekDay = "";
Calendar c = Calendar.getInstance();
int dayOfWeek = c.get(Calendar.DAY_OF_WEEK);
if (Calendar.MONDAY == dayOfWeek) {
weekDay = "monday";
} else if (Calendar.TUESDAY == dayOfWeek) {
weekDay = "tuesday";
} else if (Calendar.WEDNESDAY == dayOfWeek) {
weekDay = "wednesday";
} else if (Calendar.THURSDAY == dayOfWeek) {
weekDay = "thursday";
} else if (Calendar.FRIDAY == dayOfWeek) {
weekDay = "friday";
} else if (Calendar.SATURDAY == dayOfWeek) {
weekDay = "saturday";
} else if (Calendar.SUNDAY == dayOfWeek) {
weekDay = "sunday";
}
System.out.println(weekDay);
}
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