使用Jersey通过RESTfull服务上传文件和资源配置是不可修改的？

Question

@Path("file.upload")
public class UploadFileService {
@POST
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadFile(
        @FormDataParam("file") InputStream uploadedInputStream,
        @FormDataParam("file") FormDataContentDisposition fileDetail) {

    System.out.println("-----------------UploadFileService------------------1.");
    // Should we use a disk or DB? Decided to use DISK
    // Path should be read from properties-files
    String uploadedFileLocation = "//uploaded/" + fileDetail.getFileName();

    // save it
    writeToFile(uploadedInputStream, uploadedFileLocation);

    String output = "File uploaded to : " + uploadedFileLocation;
    // All went OK
    return Response.status(200).entity(output).build();

}

 WARNING: No injection source found for a parameter of type public javax.ws.rs.core.Response com.insame.service.UploadFileService.uploadFile(java.io.InputStream,com.sun.jersey.core.header.FormDataContentDisposition) at index 0.

SEVERE:   WebModule[/insame]StandardWrapper.Throwable
org.glassfish.jersey.server.model.ModelValidationException: Validation of the application resource model has failed during application initialization.
[[FATAL] No injection source found for a parameter of type public javax.ws.rs.core.Response com.insame.service.UploadFileService.uploadFile(java.io.InputStream,com.sun.jersey.core.header.FormDataContentDisposition) at index 0.; source='ResourceMethod{httpMethod=POST, consumedTypes=[multipart/form-data], producedTypes=[], suspended=false, suspendTimeout=0, suspendTimeoutUnit=MILLISECONDS, invocable=Invocable{handler=MethodHandler{handlerClass=class com.insame.service.UploadFileService, handlerConstructors=[org.glassfish.jersey.server.model.HandlerConstructor@47bee27a]}, handlingMethod=public javax.ws.rs.core.Response com.insame.service.UploadFileService.uploadFile(java.io.InputStream,com.sun.jersey.core.header.FormDataContentDisposition), parameters=[Parameter [type=class java.io.InputStream, source=file, defaultValue=null], Parameter [type=class com.sun.jersey.core.header.FormDataContentDisposition, source=file, defaultValue=null]], responseType=class javax.ws.rs.core.Response}, nameBindings=[]}']
    at org.glassfish.jersey.server.ApplicationHandler.initialize(ApplicationHandler.java:410)
    at org.glassfish.jersey.server.ApplicationHandler.access$500(ApplicationHandler.java:157)
    at org.glassfish.jersey.server.ApplicationHandler$3.run(ApplicationHandler.java:280)
    at org.glassfish.jersey.internal.Errors$2.call(Errors.java:289)
    at org.glassfish.jersey.internal.Errors$2.call(Errors.java:286)
    at org.glassfish.jersey.internal.Errors.process(Errors.java:315)
    at org.glassfish.jersey.internal.Errors.process(Errors.java:297)
    at org.glassfish.jersey.internal.Errors.processWithException(Errors.java:286)
    at org.glassfish.jersey.server.ApplicationHandler.<init>(ApplicationHandler.java:277)
    at org.glassfish.jersey.servlet.WebComponent.<init>(WebComponent.java:262)
    at org.glassfish.jersey.servlet.ServletContainer.init(ServletContainer.java:167)

我在下面实现了这样的测试服务UploadFileService:

@GET
@Path("count")
@Produces("text/plain")
public String countREST() {
    return "1 one 1";
}

我得到了这个例外记录:

FINE:   [Web-Security] hasResource perm: ("javax.security.jacc.WebResourcePermission" 

"/webresources/file.upload/count" "GET")
SEVERE:   WebModule[/insame]StandardWrapper.Throwable
java.lang.IllegalStateException: The resource configuration is not modifiable in this context.
    at org.glassfish.jersey.server.ResourceConfig$ImmutableState.register(ResourceConfig.java:257)
WARNING:   StandardWrapperValve[com.insame.service.ApplicationConfig]: Allocate exception for servlet com.insame.service.ApplicationConfig
java.lang.IllegalStateException: The resource configuration is not modifiable in this context.
    at org.glassfish.jersey.server.ResourceConfig$ImmutableState.register(ResourceConfig.java:257)
    at org.glassfish.jersey.server.ResourceConfig$ImmutableState.register(ResourceConfig.java:205)
    at org.glassfish.jersey.server.ResourceConfig.register(ResourceConfig.java:435)
    at org.glassfish.jersey.servlet.WebComponent.<init>(WebComponent.java:261)
    at org.glassfish.jersey.servlet.ServletContainer.init(ServletContainer.java:167)
    at org.glassfish.jersey.servlet.ServletContainer.init(ServletContainer.java:349)

环境

• Netbeans7.3.1
• Glassfish 4.0
• 泽西2与Glassfish 4.0

Answer 1

要在Jersey应用程序中使用multipart,您需要在应用程序中注册MultiPartFeature,即:

public class ApplicationConfig extends Application {

    public Set<Class<?>> getClasses() {
        final Set<Class<?>> resources = new HashSet<Class<?>>();

        // Add your resources.
        resources.add(UploadFileService.class);

        // Add additional features such as support for Multipart.
        resources.add(MultiPartFeature.class);

        return resources;
    }
}

有关更多信息,请参阅Jersey用户指南中的" 多部分"部分.

对于第二个问题,您正试图重新启动GlassFish服务器,我不确定NetBeans在更改后如何重新加载Jersey应用程序(如果这没有帮助,请发布您的ApplicationConfig).

Answer 2

我遇到了同样的问题,并希望避免创建自定义应用程序类.它没有很好的文档,但是如果你想添加Multipart功能,你所要做的就是将它添加到你的web.xml jersey servlet配置中:

<init-param>
    <param-name>jersey.config.server.provider.classnames</param-name>
    <param-value>org.glassfish.jersey.filter.LoggingFilter;org.glassfish.jersey.media.multipart.MultiPartFeature</param-value>
</init-param>

我还添加了一个loggingfilter.