Sun*_*ang 6 xaml listview windows-8
我在win8中使用listview控件.我想在我按住项目时添加一个事件,然后删除该项目.
像这样的xaml和事件代码:
<ListView x:Name="ImageList" VerticalAlignment="Bottom" Background="LightGray" Width="1050" BorderBrush="Black" BorderThickness="2" Grid.Column="1"
Holding="ListView_Hold1" SelectionChanged="OnSelectedChanged" SelectionMode="Single" Height="152" ScrollViewer.HorizontalScrollBarVisibility="Auto" ItemContainerStyle="{StaticResource ListViewItemStyle1}" Style="{StaticResource ListViewStyle1}">
<ListView.ItemTemplate>
<DataTemplate>
<Image Opacity="0.7" Width="150" Height="125" Stretch="UniformToFill" Source="{Binding}" />
</DataTemplate>
</ListView.ItemTemplate>
<ListView.ItemsPanel>
<ItemsPanelTemplate>
<VirtualizingStackPanel Orientation="Horizontal"/>
</ItemsPanelTemplate>
</ListView.ItemsPanel>
</ListView>
private async void ListView_Hold1(object sender, Windows.UI.Xaml.Input.HoldingRoutedEventArgs e)
{...}
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似乎我无法从holdingroutdEventArgs获取任何信息,而是来自originalsource的属性.但它是图像,无法访问iteml
我找到了一个相对的问题:"如何在listview中获取被点击的项目".它可以通过获取selecteditem的属性来解决.
有人可以帮帮我吗?给我一些线索.
HoldingRoutedEventArgs.OriginalSource.DataContext
在你的情况下,你应该能够从中得到它:(假设它ListView.ItemSource
是一个列表ImageModel
)
private async void ListView_Hold1(object sender, Windows.UI.Xaml.Input.HoldingRoutedEventArgs args)
{
var source = (FrameworkElement)args.OriginalSource;
var imageModel = (ImageModel)source.DataContext;
}
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