mil*_*ble 1 c# xml serialization
我有一个如下所示的 XML 文件:
<Categories>
<Category Name="Mobile">
<SubCategory Name="Mobile Phones" MarkUp="1.2">
<Mapping Category1="COMMUNICATION" Category2="PHONE" Category3="MOBILE" Category4="MOBILE PHONE" Category5="ANDROID" Category6="" Category7="" />
<Mapping Category1="COMMUNICATION" Category2="PHONE" Category3="MOBILE" Category4="MOBILE PHONE" Category5="BLACKBERRY OS" Category6="" Category7="" />
<Mapping Category1="COMMUNICATION" Category2="PHONE" Category3="MOBILE" Category4="MOBILE PHONE" Category5="OTHER" Category6="" Category7="" />
<Mapping Category1="COMMUNICATION" Category2="PHONE" Category3="MOBILE" Category4="MOBILE PHONE" Category5="SYMBIAN" Category6="" Category7="" />
<Mapping Category1="COMMUNICATION" Category2="PHONE" Category3="MOBILE" Category4="MOBILE PHONE" Category5="WINDOWS PHONE" Category6="" Category7="" />
</SubCategory>
</Categories>
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我目前正在像这样反序列化:
[XmlRoot(ElementName = "Category")]
public class XmlCategory
{
[XmlAttribute(AttributeName = "Name")]
public string Name { get; set; }
[XmlElement("SubCategory")]
public XmlSubCategory[] XmlSubCategories { get; set; }
}
public class XmlSubCategory
{
[XmlAttribute(AttributeName = "Name")]
public string Name { get; set; }
[XmlAttribute(AttributeName = "MarkUp")]
public string MarkUp { get; set; }
[XmlElement("Mapping")]
public XmlMapping[] Mappings { get; set; }
}
public class XmlMapping
{
[XmlAttribute(AttributeName = "Category1")]
public string Category1 { get; set; }
// etc.
}
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问题在于映射节点 - 我宁愿获取它的属性集合,然后为每个属性创建一个字符串 - 我不确定如何解决这个问题 - 我已经尝试使用 XmlAnyAttribute 和 XmlArrayItem
干杯
是的,您可以XmlAnyAttribute在这里使用,尽管我个人建议显式成员方法要优越得多,即您的
public class XmlMapping
{
[XmlAttribute] public string Category1 { get; set; }
[XmlAttribute] public string Category2 { get; set; }
[XmlAttribute] public string Category3 { get; set; }
[XmlAttribute] public string Category4 { get; set; }
[XmlAttribute] public string Category5 { get; set; }
[XmlAttribute] public string Category6 { get; set; }
[XmlAttribute] public string Category7 { get; set; }
}
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但是,这也有效:
public class XmlMapping
{
[XmlAnyAttribute]
public XmlAttribute[] Attributes { get; set; }
}
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然后枚举它:
foreach (var map in subCat.Mappings)
{
var attribs = map.Attributes;
if (attribs != null)
{
foreach (var attrib in attribs)
{
System.Console.WriteLine("{0}={1}", attrib.Name, attrib.Value);
}
}
}
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对我来说很好用......(虽然我必须修复你损坏的 xml - 缺少结束标签)