bay*_*uah 2 php native function
我试图从数组中创建字符串序列逗号.这是我使用的代码:
<?php
echo "I eat " . implode(', ',array('satay','orange','rambutan'));
?>
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但结果我得到:
I eat satay, orange, rambutan
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不能:
I eat satay, orange, and rambutan
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然而!
所以,我做了自己的功能:
<?php
function array_to_serial_comma($ari,$konj=" and ",$delimiter=",",$space=" "){
// If not array, then quit
if(!is_array($ari)){
return false;
};
$rturn=array();
// If more than two
// then do actions
if(count($ari)>2){
// Reverse array
$ariBlk=array_reverse($ari,false);
foreach($ariBlk as $no=>$c){
if($no>=(count($ariBlk)-1)){
$rturn[]=$c.$delimiter;
}else{
$rturn[]=($no==0)?
$konj.$c
: $space.$c.$delimiter;
};
};
// Reverse array
// to original
$rturn=array_reverse($rturn,false);
$rturn=implode($rturn);
}else{
// If >=2 then regular merger
$rturn=implode($konj,$ari);
};
// Return
return $rturn;
};
?>
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从而:
<?php
$eat = array_to_serial_comma(array('satay','orange','rambutan'));
echo "I eat $eat";
?>
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结果:
I eat satay, orange, and rambutan
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是否有更有效的方法,使用本机PHP函数可能?
编辑:
基于@Mash的代码,我修改了可能有用的代码:
<?php
function array_to_serial_comma($ari,$konj=" and ",$delimiter=",",$space=" "){
// If not array, then quit
if(!is_array($ari)){
return false;
};
$rturn=array();
// If more than two
// then do actions
if(count($ari)>2){
$akr = array_pop($ari);
$rturn = implode($delimiter.$space, $ari) . $delimiter.$konj.$akr;
}else{
// If >=2 then regular merger
$rturn=implode($konj,$ari);
};
// Return
return $rturn;
};
?>
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这是一个更清洁的方式:
<?php
$array = array('satay','orange','rambutan');
$last = array_pop($array);
echo "I eat " . implode(', ', $array) . ", and " . $last;
?>
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array_pop() 将最后一个元素从数组中取出并分配给它 $last