use*_*964 -4 .net c# async-await
我的代码有问题.我怎么解决这个问题?等待运算符中存在此问题.
public MyModel()
{
HttpClient client = new HttpClient();
HttpResponseMessage response = await client.GetAsync("https://api.vkontakte.ru/method/video.get?uid=219171498&access_token=d61b93dfded2a37dfcfa63779efdb149653292636cac442e53dae9ba6a049a75637143e318cc79e826149");
string googleSearchText = await response.Content.ReadAsStringAsync();
JObject googleSearch = JObject.Parse(googleSearchText);
IList<JToken> results = googleSearch["response"].Children().Skip(1).ToList();
IList<MainPage1> searchResults = new List<MainPage1>();
foreach (JToken result in results)
{
MainPage1 searchResult = JsonConvert.DeserializeObject<MainPage1>(result.ToString());
searchResults.Add(searchResult);
}
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您正尝试await在构造函数中使用.你做不到 - 构造函数总是同步的.
您只能await在方法或匿名函数中使用async修饰符; 你不能将该修饰符应用于构造函数.
解决这个问题的一种方法是创建一个静态异步方法来创建一个实例 - 它将执行所有相关的等待,然后将结果传递给一个简单的同步构造函数.当然,你的呼叫者需要适当地处理这个问题.
public static async Task<MyModel> CreateInstance()
{
string googleSearchText;
using (HttpClient client = new HttpClient())
{
using (HttpResponseMessage response = await client.GetAsync(...))
{
googleSearchText = await response.Content.ReadAsStringAsync();
}
}
// Synchronous constructor to do the rest...
return new MyModel(googleSearchText);
}
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您不能在类的构造函数中使用await.
异步方法返回一个Task可以执行异步的对象.构造函数没有返回类型,因此无法返回Task对象,因此无法等待.
解决此问题的一个简单方法是创建一个Init函数:
public MyModel()
{
}
public async Task Init()
{
HttpClient client = new HttpClient();
HttpResponseMessage response = await client.GetAsync("https://api.vkontakte.ru/method/video.get?uid=219171498&access_token=d61b93dfded2a37dfcfa63779efdb149653292636cac442e53dae9ba6a049a75637143e318cc79e826149");
string googleSearchText = await response.Content.ReadAsStringAsync();
JObject googleSearch = JObject.Parse(googleSearchText);
IList<JToken> results = googleSearch["response"].Children().Skip(1).ToList();
IList<MainPage1> searchResults = new List<MainPage1>();
foreach (JToken result in results)
{
MainPage1 searchResult = JsonConvert.DeserializeObject<MainPage1>(result.ToString());
searchResults.Add(searchResult);
}
}
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然后在创建模型时:
var model = new MyModel();
await model.Init();
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