我希望能够创建扩展MySQLi类的类来执行所有SQL查询.
$mysql = new mysqli('localhost', 'root', 'password', 'database') or die('error connecting to the database');
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我不知道如何在没有全局化$ mysql对象的情况下执行此操作以在我的其他方法或类中使用.
class Blog {
public function comment() {
global $mysql;
//rest here
}
}
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任何帮助,将不胜感激.
谢谢.
Yad*_*ada 12
我正在做类似的事情.我对这个封装数据库登录的单例类感到高兴.
<?php
class db extends mysqli
{
protected static $instance;
protected static $options = array();
private function __construct() {
$o = self::$options;
// turn of error reporting
mysqli_report(MYSQLI_REPORT_OFF);
// connect to database
@parent::__construct(isset($o['host']) ? $o['host'] : 'localhost',
isset($o['user']) ? $o['user'] : 'root',
isset($o['pass']) ? $o['pass'] : '',
isset($o['dbname']) ? $o['dbname'] : 'world',
isset($o['port']) ? $o['port'] : 3306,
isset($o['sock']) ? $o['sock'] : false );
// check if a connection established
if( mysqli_connect_errno() ) {
throw new exception(mysqli_connect_error(), mysqli_connect_errno());
}
}
public static function getInstance() {
if( !self::$instance ) {
self::$instance = new self();
}
return self::$instance;
}
public static function setOptions( array $opt ) {
self::$options = array_merge(self::$options, $opt);
}
public function query($query) {
if( !$this->real_query($query) ) {
throw new exception( $this->error, $this->errno );
}
$result = new mysqli_result($this);
return $result;
}
public function prepare($query) {
$stmt = new mysqli_stmt($this, $query);
return $stmt;
}
}
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要使用你可以有这样的东西:
<?php
require "db.class.php";
$sql = db::getInstance();
$result = $sql->query("select * from city");
/* Fetch the results of the query */
while( $row = $result->fetch_assoc() ){
printf("%s (%s)\n", $row['Name'], $row['Population']);
}
?>
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