使用两个字典键基于日期和时间对数组进行排序

Mor*_*ang 1 sorting objective-c nsdate ios

我正在尝试根据日期和时间对数组进行排序,我可以根据日期成功对数组进行排序,这两个时间即将作为字典中的另一个值.

所以date是格式化的字符串"yyyy-MM-dd",时间是格式化的字符串"HH:mm"

时间值"starts"以字符串'"HH:mm"'格式输入.

我知道我需要结合两个字符串,'yyyy-MM-dd HH:mm'但如何?

-(NSMutableArray *)sortArrayBasedOndate:(NSMutableArray *)arraytoSort
{
    NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
    [formatter setDateFormat:@"yyyy-MM-dd"];

    NSComparator compareDates = ^(id string1, id string2)
    {
        NSDate *date1 = [formatter dateFromString:string1];
        NSDate *date2 = [formatter dateFromString:string2];

        return [date1 compare:date2];
    };


    NSSortDescriptor * sortDesc1 = [[NSSortDescriptor alloc] initWithKey:@"start_date" ascending:YES comparator:compareDates];
    [arraytoSort sortUsingDescriptors:[NSArray arrayWithObjects:sortDesc1, nil]];


    return arraytoSort;
}
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不知道怎样才能解决这个问题?

Joe*_*Joe 9

你需要对时间进行排序,这就是为什么sortUsingDescriptors:需要一个数组.

-(NSMutableArray *)sortArrayBasedOndate:(NSMutableArray *)arraytoSort
{
    NSDateFormatter *fmtDate = [[NSDateFormatter alloc] init];
    [fmtDate setDateFormat:@"yyyy-MM-dd"];

    NSDateFormatter *fmtTime = [[NSDateFormatter alloc] init];
    [fmtTime setDateFormat:@"HH:mm"];

    NSComparator compareDates = ^(id string1, id string2)
    {
        NSDate *date1 = [fmtDate dateFromString:string1];
        NSDate *date2 = [fmtDate dateFromString:string2];

        return [date1 compare:date2];
    };

    NSComparator compareTimes = ^(id string1, id string2)
    {
        NSDate *time1 = [fmtTime dateFromString:string1];
        NSDate *time2 = [fmtTime dateFromString:string2];

        return [time1 compare:time2];
    };

    NSSortDescriptor * sortDesc1 = [[NSSortDescriptor alloc] initWithKey:@"start_date" ascending:YES comparator:compareDates];
    NSSortDescriptor * sortDesc2 = [NSSortDescriptor sortDescriptorWithKey:@"starts" ascending:YES comparator:compareTimes];
    [arraytoSort sortUsingDescriptors:@[sortDesc1, sortDesc2]];

    return arraytoSort;
}
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