Shi*_*dla 4 django model save integrity slug
我有一个包含两个字段的模型,如下所示
模型.py
class Publisher(models.Model):
name = models.CharField(max_length=200)
slug = models.SlugField(max_length=150, unique=True)
def save(self, *args, **kwargs):
if not self.id and not self.slug:
slug = slugify(self.name)
try:
slug_exits = Publisher.objects.get(slug=slug)
if slug_exits:
self.slug = slug + '_1'
except Publisher.DoesNotExist:
self.slug = slug
super(Publisher, self).save(*args, **kwargs)
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name正如我们在上面看到的,我在这里创建了一个基于字段的 slug
因此,当我们尝试使用 来创建发布者时name already exists,save模型的方法会_1在末尾添加。
当我们再次尝试创建相同的新记录时name,Integrity将引发如下错误
>> Publisher.objects.create(name="abc")
result: slug will be "abc"
>> Publisher.objects.create(name="abc")
result: slug will be "abc_1"
>> Publisher.objects.create(name="abc")
result:
.................
.................
34 del cursor
35 del connection
---> 36 raise errorclass, errorvalue
37
38 re_numeric_part = re.compile(r"^(\d+)")
IntegrityError: (1062, "Duplicate entry 'abc_1' for key 'slug'")
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所以我想要的是,如果标题/slug 已经存在于数据库中,并且如果 slug 中包含数字(最后像 abc _1),我们应该增加它的数字
所以increment the number in the slug 如果标题/slug已经存在于数据库中,我想要的就是如下
abc
abc_1
abc_2
abc_3
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那么任何人都可以让我知道如何实现上述增加 slug 的逻辑吗?
提前致谢......
您将不得不使用循环而不仅仅是一个条件。尝试这个:
class Publisher(models.Model):
name = models.CharField(max_length=200)
slug = models.SlugField(max_length=150, unique=True)
def save(self, *args, **kwargs):
if not self.id and not self.slug:
slug = slugify(self.name)
slug_exists = True
counter = 1
self.slug = slug
while slug_exists:
try:
slug_exits = Publisher.objects.get(slug=slug)
if slug_exits:
slug = self.slug + '_' + str(counter)
counter += 1
except Publisher.DoesNotExist:
self.slug = slug
break
super(Publisher, self).save(*args, **kwargs)
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