标准容器的复杂性保证是什么？

Question

显然;-)标准容器提供某种形式的保证.

什么类型的保证以及不同类型的容器之间究竟有什么区别？

从工作的SGI页(约STL)我想出了这一点:

Container Types:
================
Container:
    Forward Container
        Reverse Container
            Random Access Container
    Sequence
        Front Insert Sequence
        Back  Insert Sequence
    Associative Container
        Simple   Associative Container
        Pair     Associative Container
        Sorted   Associative Container
        Multiple Associative Container

Container Types mapped to Standard Containers
=============================================

std::vector:    Sequence    Back        Sequence                    Forward/Reverse/Random Container
std::deque:     Sequence    Front/Back  Sequence                    Forward/Reverse/Random Container
std::list:      Sequence    Front/Back  Sequence                    Forward/Reverse Container
std::set:       Sorted/Simple/Unique    Associative Container       Forward Container
std::map:       Sorted/Pair/Unique      Associative Container       Forward Container
std::multiset:  Sorted/Simple/Multiple  Associative Container       Forward Container
std::multimap:  Sorted/Pair/Multiple    Associative Container       Forward Container


Container Guarantees:
=====================

                                                                                  Simp
                                                                                  or
                          For   Rev  Rand        Front  Back  Assoc        Sort   Mult
                    Cont: Cont: Cont Cont: Sequ: Sequ:  Sequ: Cont:        Cont:  Cont:
Copy    Const:      O(n)
Fill    Const:                             O(n)
begin()             O(1)
end()               O(1)
rbegin()                        O(1)
rend()                          O(1)
front()                                    O(1)
push_front()                                     O(1)
pop_front()                                      O(1)
push_back()                                             O(1)
pop_back()                                              O(1)
Insert()                                                                          O(ln(n))
Insert: fill                               O(n)
Insert: range                              O(n)                                   O(kln(n)+n)
size()              O(n)
swap()              O(1)
erase key                                                     O(ln(n))
erase element                                                 O(1)
erase range                                                   O(ln(n)+S)
count()                                                       O(log(n)+k)
find()                                                        O(ln(n))
equal range                                                   O(ln(n))
Lower Bound/Upper Bound                                                    O(ln(n))
Equality                  O(n)
InEquality                O(n)
Element Access                       O(1)

Answer 1

我找到了很好的资源标准C++容器.可能这就是你们都在寻找的东西.

向量

构造函数

vector<T> v;              Make an empty vector.                                     O(1)
vector<T> v(n);           Make a vector with N elements.                            O(n)
vector<T> v(n, value);    Make a vector with N elements, initialized to value.      O(n)
vector<T> v(begin, end);  Make a vector and copy the elements from begin to end.    O(n)

访问器

v[i]          Return (or set) the I'th element.                        O(1)
v.at(i)       Return (or set) the I'th element, with bounds checking.  O(1)
v.size()      Return current number of elements.                       O(1)
v.empty()     Return true if vector is empty.                          O(1)
v.begin()     Return random access iterator to start.                  O(1)
v.end()       Return random access iterator to end.                    O(1)
v.front()     Return the first element.                                O(1)
v.back()      Return the last element.                                 O(1)
v.capacity()  Return maximum number of elements.                       O(1)

修饰符

v.push_back(value)         Add value to end.                                                O(1) (amortized)
v.insert(iterator, value)  Insert value at the position indexed by iterator.                O(n)
v.pop_back()               Remove value from end.                                           O(1)
v.assign(begin, end)       Clear the container and copy in the elements from begin to end.  O(n)
v.erase(iterator)          Erase value indexed by iterator.                                 O(n)
v.erase(begin, end)        Erase the elements from begin to end.                            O(n)

有关其他容器,请参阅该页面.

Answer 2

我不知道有什么像一张桌子可以让你一目了然地比较所有这些(我不确定这样的桌子是否可行).

当然,ISO标准文档详细列举了复杂性要求,有时在各种相当可读的表中,有时在每个特定方法的可读性较低的要点中.

此外,http: //www.cplusplus.com/reference/stl/上的STL库参考资料还提供了适当的复杂性要求.