use*_*679 0 java sql hibernate exception
List<Candidate> candidates = (List<Candidate>) session.createSQLQuery("select candidate.* from candidate inner join candidate_skill on candidate.id = candidate_skill.candidate_id inner join skill on candidate_skill.skill_id = skill.id where skill.id = 1");
Run Code Online (Sandbox Code Playgroud)
我明白了:
java.lang.ClassCastException: org.hibernate.internal.SQLQueryImpl cannot be cast to java.util.List
Run Code Online (Sandbox Code Playgroud)
查询是正确的.怎么解决?
kos*_*osa 12
你忘记.list()
了查询的结尾.
应该是这样的
................skill.id where skill.id = 1").list();
Run Code Online (Sandbox Code Playgroud)
有关更多信息,请参阅hibernate文档.
归档时间: |
|
查看次数: |
12664 次 |
最近记录: |