将Ruby数组解析为JSON

pab*_*808 9 ruby json

我有一些结果:

puts result
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看起来像这样的输出:

Allowed
20863963
1554906
Denied
3607325
0
Quarantined
156240 
0
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调试

p results
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产量

[["Allowed", 20863963, 1554906], ["Denied", 3607325, 0], ["Quarantined", 156194, 0]]
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标题是:

status,hits,page_views 
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我需要将其转换为json.如果结果是标准的csv格式,那么它将是直截了当的,但如果结果格式如上所示,如何处理它?

预期输出与此类似:

[{"status":"Allowed","hits":"20863963","page_views":"1554906"},{"status":"Denied","hits":"3607325","page_views":"0"},{"status":"Quarantined","hits":"156240","page_views":"0"}]
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a = result.map{|s| {status: s[0], hits: s[1].to_i, page_views: s[2].to_i} }
puts a.to_json
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bma*_*ets 15

to_json方法.

require 'json'
# => true 
h = {a: 1, b: 2,c: 3}
# => {a: 1, b: 2,c: 3}
h.to_json
# => "{\"a\":1,\"b\":2,\"c\":3}" 
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Abe*_*ker 5

output = "Allowed
20863963
1554906
Denied
3607325
0
Quarantined
156240 
0"

a = output.split("\n").each_slice(3).map{|s| {status: s[0], hits: s[1].to_i, page_views: s[2].to_i} } # => [{:status=>"Allowed", :hits=>20863963, :page_views=>1554906}, {:status=>"Denied", :hits=>3607325, :page_views=>0}, {:status=>"Quarantined", :hits=>156240, :page_views=>0}]
a.to_json # => => "[{\"status\":\"Allowed\",\"hits\":20863963,\"page_views\":1554906},{\"status\":\"Denied\",\"hits\":3607325,\"page_views\":0},{\"status\":\"Quarantined\",\"hits\":156240,\"page_views\":0}]"
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