ebb*_*ebb 5 asp.net-mvc f# asynchronous
使用C# - ASP.NET MVC 4,我可以定义一个异步控制器动作,如:
public async Task<ActionResult> IndexWorks()
{
var data = await DownloadAsync("http://stackoverflow.com");
return Content(data);
}
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有没有办法做类似的事情,使用F#?
我知道我可以使用这种AsyncManager
方法.我也知道@Tomas Petricek做得很整洁AsyncActionBuilder
,但与C#方法相比,感觉就像很多样板.
async/await使用Tasks,因此您需要在Task对象和F#Async对象之间来回转换.要从Task转换为Async,请使用Async.AwaitTask
.做相反的用法Async.StartAsTask
.你的例子变成:
member x.IndexWorks() =
async {
let! data = Async.AwaitTask (DownloadAsync "http://stackoverflow.com")
return x.Content(data)
} |> Async.StartAsTask
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或者,async
您可以使用适用于开箱即用的任务的计算表达式,而不是使用计算表达式.FSharpx中有一个:
let task = FSharpx.Task.TaskBuilder()
(...)
member x.IndexWorks() = task {
let! data = DownloadAsync "http://stackoverflow.com"
return x.Content(data)
}
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实际上,看起来像一位程序员同事德米特里·莫罗佐夫(Dmitry Morozov)已经使这样的事情成为可能。他制定了一个习惯,使得从一个地方AsyncWorkflowController
回来成为可能。代码可以在http://fssnip.net/5q找到。Async<ActionResult>
ActionResult
AsyncWorkFlowController
然而,他的实现使得调试非常困难,因为在自定义控制器中重新抛出时不会保留堆栈跟踪。因此我做了一些改变来实现这一点:
member actionDesc.EndExecute(asyncResult) =
match endAsync'.Value(asyncResult) with
| Choice1Of2 value -> box value
| Choice2Of2 why ->
// Preserve the stack trace, when rethrow
ExceptionDispatchInfo.Capture(why).Throw()
obj() (* Satisfy return value *) } } }
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我还更改了以下行:new ReflectedControllerDescriptor(controllerType)
,
to new ReflectedAsyncControllerDescriptor(controllerType)
- 然而,此更改纯粹是可选的,因为它不会产生任何影响。我只是发现使用这个更合乎逻辑Async
。
完整的代码将是:
open System
open System.Web.Mvc
open System.Web.Mvc.Async
open System.Runtime.ExceptionServices
open Unchecked
type AsyncWorkflowController() =
inherit AsyncController()
override __.CreateActionInvoker() =
upcast { new AsyncControllerActionInvoker() with
member __.GetControllerDescriptor(controllerContext) =
let controllerType = controllerContext.Controller.GetType()
upcast { new ReflectedAsyncControllerDescriptor(controllerType) with
member ctrlDesc.FindAction(controllerContext, actionName) =
let forwarder = base.FindAction(controllerContext, actionName) :?> ReflectedActionDescriptor
if(forwarder = null || forwarder.MethodInfo.ReturnType <> typeof<Async<ActionResult>>) then
upcast forwarder
else
let endAsync' = ref (defaultof<IAsyncResult -> Choice<ActionResult, exn>>)
upcast { new AsyncActionDescriptor() with
member actionDesc.ActionName = forwarder.ActionName
member actionDesc.ControllerDescriptor = upcast ctrlDesc
member actionDesc.GetParameters() = forwarder.GetParameters()
member actionDesc.BeginExecute(controllerContext, parameters, callback, state) =
let asyncWorkflow =
forwarder.Execute(controllerContext, parameters) :?> Async<ActionResult>
|> Async.Catch
let beginAsync, endAsync, _ = Async.AsBeginEnd(fun () -> asyncWorkflow)
endAsync' := endAsync
beginAsync((), callback, state)
member actionDesc.EndExecute(asyncResult) =
match endAsync'.Value(asyncResult) with
| Choice1Of2 value -> box value
| Choice2Of2 why ->
// Preserve the stack trace, when rethrow
ExceptionDispatchInfo.Capture(why).Throw()
obj() (* Satisfy return value *) } } }
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用法:
type TestController() =
inherit AsyncWorkflowController()
member x.IndexWorks() = async {
let startThread = Thread.CurrentThread.ManagedThreadId
let! data = asyncDownload "http://stackoverflow.com"
let endThread = Thread.CurrentThread.ManagaedThreadId
return ContentResult(Content = "Start = %i | End = %i" startThread endThread) :> ActionResult }
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要确认它实际上异步执行所有操作,并且没有阻止 ASP.NET 池中的任何线程,请使用:
member x.IndexWorks() = async {
let startThread = Thread.CurrentThread.ManagedThreadId
let! data = asyncDownload "http://stackoverflow.com"
let endThread = Thread.CurrentThread.ManagaedThreadId
return ContentResult(Content = "Start = %i | End = %i" startThread endThread) :> ActionResult }
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起始线程和结束线程将不同,因此起始线程被放回到池中,并且当异步操作完成时返回一个新线程。
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