blu*_*row 5 mysql sql group-by sql-update
我在MYSQL中有一个表:
CREATE TABLE test.tem(a INT,b INT);
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以下数据:
INSERT INTO test.tem VALUES(1,2),(1,1),(1,NULL),(2,3);
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现在数据应该是:
+------+------+
| a | b |
+------+------+
| 1 | 2 |
| 1 | 1 |
| 1 | NULL |
| 2 | 3 |
+------+------+
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我想按列a将列b更新到min(b)组.
所以SQL应该是:
UPDATE test.tem o
SET o.b = (SELECT
MIN(b)
FROM test.tem i
WHERE i.a = o.a)
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但是MYSQL 无法在FROM子句中指定更新目标表
所以我认为下面的SQL可以很好地解决我的问题:
UPDATE test.tem t1
JOIN test.tem t2
ON t1.a = t2.a
SET t1.b = t2.b
WHERE t1.b IS NULL
OR t1.b > t2.b;
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但结果是:
+------+------+
| a | b |
+------+------+
| 1 | 1 |
| 1 | 1 |
| 1 | 2 |
| 2 | 3 |
+------+------+
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其实我需要的结果是:
+------+------+
| a | b |
+------+------+
| 1 | 1 |
| 1 | 1 |
| 1 | 1 |
| 2 | 3 |
+------+------+
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问题1:为什么MYSQL使用SQL计算出错误的结果?具有高效率的正确SQL应该是什么?
问题2:如果我只想用NULL值更新b(仅更新第三条记录),SQL应该是什么?
关于问题2,我试图使用下面不正确的SQL:
UPDATE test.tem t1
JOIN test.tem t2
ON t1.a = t2.a
AND t1.b IS NULL
SET t1.b = t2.b
WHERE t1.b IS NULL
OR t1.b > t2.b;
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您没有唯一的列来标识您的行。因此,您JOIN可能会按照您的想法更新更多行。
你可能想要类似的东西:
UPDATE tem AS t1 JOIN (SELECT a, MIN(b) AS m FROM tem GROUP BY a) AS t2
USING (a)
SET t1.b = t2.m;
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请参阅http://sqlfiddle.com/#!2/c6a04/1
如果您只想更新bNULL列中的行,这只是子句的问题:WHERE
CREATE TABLE tem(a INT,b INT);
INSERT INTO tem VALUES(1,2),(1,1),(1,NULL),(2,3);
UPDATE tem AS t1 JOIN (SELECT a, MIN(b) AS m FROM tem GROUP BY a) AS t2
USING (a)
SET t1.b = t2.m
WHERE t1.b IS NULL;
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请参阅http://sqlfiddle.com/#!2/31ffb/1