c中的strlen返回否定结果

Question

程序片段: -

if((fd = open(buf_serv, O_RDONLY)) < 0) {
    char c[MAXLEN+1];
    snprintf(c, sizeof(c), ": can't open, %s\n", strerror(errno));
    n = strlen(c);

...

gdb :-
102     if((fd = open(buf_serv, O_RDONLY)) < 0) {
(gdb) n
104        snprintf(c, sizeof(c), ": can't open, %s\n", strerror(errno));
(gdb) p sizeof(c)
$1 = 4097
(gdb) n
105        n = strlen(c);
(gdb) p strlen(c)
$2 = -1428323296
(gdb) n
...

任何人都可以告诉我strlen如何返回负数？(用sigsegv信号撞击我的程序)

在此先感谢所有人!

(gdb) l
101
102     if((fd = open(buf_serv, O_RDONLY)) < 0) {
103        char ch[MAXLEN+1];
104        write(STDOUT_FILENO, "foo", 3);
105        sprintf(ch, ": can't open, %s\n", strerror(errno));
106        n = strlen(ch);
107        write(writefd, ch, 100);
108     } else {
109        while((n = read(fd, buf_serv, MAXLEN)) > 0) {
110             write(writefd, buf_serv, n);
(gdb) p ch
$1 = ": can't open, No such file or directory\n", '\000' <repeats 4056 times>
(gdb) p strlen(ch)
$2 = -1428323296

Answer 1

只是你不能使用GDB:P

(gdb) n
105        n = strlen(c);
(gdb) p strlen(c)

GDB显示了要执行的下一行.因此,在您打印时n,它尚未初始化.写n <enter>在打印前一个更多的时间n.