kma*_*oor 13 criteria-api jpa-2.0
我正在尝试更改以下HQL以使用JPA Criteria:
select distinct d from Department d
left join fetch d.children c
where d.parent is null
and (
d.name like :term
or c.name like :term
)
order by d.name
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Department
有一个Set<Department>
孩子.
标准:
CriteriaBuilder cb = getEntityManager().getCriteriaBuilder();
CriteriaQuery<Department> c = cb.createQuery(Department.class);
Root<Department> root = c.from(Department.class);
root.fetch("children", JoinType.LEFT);
Path<Department> children = root.join("children", JoinType.LEFT);
c.orderBy(cb.asc(root.get("name")));
c.distinct(true);
c.where(cb.isNull(root.get("parent")));
String param = "%" + "term" + "%";
cb.and(cb.like(root.<String> get("name"), param));
cb.or(cb.like(children.<String> get("name"), param));
TypedQuery<Department> tq = getEntityManager().createQuery(c);
departments = tq.getResultList();
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我知道它可能有点简洁,但是,HQL返回24和Criteria版本28.我想我不处理:
and (x = y OR z = y)
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正确.任何指针将不胜感激.谢谢.
JB *_*zet 37
这是JPQL查询的where子句:
where d.parent is null
and (
d.name like :term
or c.name like :term
)
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where子句包含两个谓词:
d.parent is null
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和
(d.name like :term
or c.name like :term)
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第二个谓词or
包含两个谓词:
d.name like :term
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和
c.name like :term
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因此,您需要在条件查询中使用相同的结构:
Predicate orClause =
cb.or(cb.like(root.<String>get("name"), param),
cb.like(children.<String>get("name"), param));
c.where(cb.isNull(root.get("parent")),
orClause);
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