使用Puppet和Vagrant配置Apache

Question

我在项目中第一次使用Vagrant和Puppet而且我一直遇到问题.

我使用PuPHPet作为起点,我在default.pp清单中有以下代码段:

class { 'apache': }

apache::dotconf { 'custom':
  content => 'EnableSendfile Off',
}

apache::module { 'rewrite': }

apache::vhost { 'awesome.dev':
  server_name   => 'awesome.dev',
  serveraliases => [
],
  docroot       => '/var/www',
  port          => '80',
  directories => [ { path => '/var/www/', allow => 'from all', allow_override => ['All'] }   ],
  env_variables => [],
  priority      => '1',
}

当我运行它时,我总是得到以下错误:

warning: Could not retrieve fact fqdn
Invalid parameter directories at /tmp/vagrant-puppet/manifests/default.pp:46 on node precise32
The following SSH command responded with a non-zero exit status.
Vagrant assumes that this means the command failed!

cd /tmp/vagrant-puppet/manifests && puppet apply --verbose --modulepath '/etc/puppet/modules:/tmp/vagrant-puppet/modules-0' default.pp --detailed-exitcodes || [ $? -eq 2 ]

第46行是apache :: vhost规则的结尾.我想将它设置为允许使用htaccess覆盖,但我无法看到我出错的地方.任何人都可以看到问题是什么？

Answer 1

PuPHPet使用Example42 Apache Puppet模块,请参阅README文件.该模块在vhost资源中没有目录参数:

https://github.com/puphpet/puphpet-apache/blob/master/manifests/vhost.pp#L100

只有Puppet Labs Apache模块有一个目录参数,但它是一个不同的模块:

https://github.com/puppetlabs/puppetlabs-apache/blob/master/manifests/vhost.pp#L25

但是,您可以使用Example42模块中的directory参数,类似于可以在vhost资源中找到的示例:

#  apache::vhost { 'my.other.site':
#    docroot                    => '/path/to/docroot',
#    directory                  => '/path/to',
#    directory_allow_override   => 'All',
#  }