在长时间的过程中与Tkinter窗口交互

Question

我有一个基本的python类,使用标准Tkinter库创建一个窗口:

import Tkinter

class GUI(Tkinter.Tk):

    def __init__(self,parent):
        Tkinter.Tk.__init__(self,parent)
        self.parent = parent
        self.initialize()

    def lock_func(self):
        while 1==1:
            print "blah"

    def initialize(self):
        self.processBtn = Tkinter.Button(self, text="Process", command=self.lock_func)
        self.processBtn.pack()        

app = GUI(None)
app.mainloop()

当我按下Process按钮时,窗口没有响应.我希望能够在运行时关闭程序(使用x按钮)lock_func.

Answer 1

您可以使用生成器来保存循环内的状态，并使用yield将控制权交还给主循环。然后使用self.after重复调用生成器的next方法来模拟while True-- 但以对 Tkinter 主循环友好的方式进行。

import Tkinter as tk

class App(object):
    def __init__(self, master):
        self.master = master
        self.initialize()

    def lock_func(self):
        def step():
            while True:
                print("blah")
                self.nextstep_id = self.master.after(1, nextstep)
                yield
        nextstep = step().next
        self.nextstep_id = self.master.after(1, nextstep)

    def stop(self):
        self.master.after_cancel(self.nextstep_id)
        print("stopped")

    def initialize(self):
        self.nextstep_id = 0
        self.process_button = tk.Button(self.master, text="Process",
                                        command=self.lock_func)
        self.stop_button = tk.Button(self.master, text="Stop",
                                     command=self.stop)        
        self.process_button.pack()
        self.stop_button.pack(expand='yes', fill='x')

root = tk.Tk()
app = App(root)
root.mainloop()