如何用彩色分支创建树状图？

Question

我想在R中创建一个树状图,它有彩色分支,如下图所示.

到目前为止,我使用以下命令创建标准树形图:

d <- dist(as.matrix(data[,29]))   # find distance matrix 
 hc <- hclust(d)                # apply hirarchical clustering 
 plot(hc,labels=data[,1], main="", xlab="") # plot the dendrogram

我该如何修改此代码以获得所需的结果？

在此先感谢您的帮助.

Answer 1

您可以使用dendextend包,旨在执行以下任务:

# install the package:
if (!require('dendextend')) install.packages('dendextend'); library('dendextend')

## Example:
dend <- as.dendrogram(hclust(dist(USArrests), "ave"))
d1=color_branches(dend,k=5, col = c(3,1,1,4,1))
plot(d1) # selective coloring of branches :)
d2=color_branches(d1,k=5) # auto-coloring 5 clusters of branches.
plot(d2)
# More examples are in ?color_branches

您可以在包的演示文稿和插图中看到许多示例,位于以下URL的"用法"部分:https://github.com/talgalili/dendextend

Answer 2

你应该使用dendrapply(帮助文档).

例如:

# Generate data
set.seed(12345)
desc.1 <- c(rnorm(10, 0, 1), rnorm(20, 10, 4))
desc.2 <- c(rnorm(5, 20, .5), rnorm(5, 5, 1.5), rnorm(20, 10, 2))
desc.3 <- c(rnorm(10, 3, .1), rnorm(15, 6, .2), rnorm(5, 5, .3))

data <- cbind(desc.1, desc.2, desc.3)

# Create dendrogram
d <- dist(data) 
hc <- as.dendrogram(hclust(d))

# Function to color branches
colbranches <- function(n, col)
  {
  a <- attributes(n) # Find the attributes of current node
  # Color edges with requested color
  attr(n, "edgePar") <- c(a$edgePar, list(col=col, lwd=2))
  n # Don't forget to return the node!
  }

# Color the first sub-branch of the first branch in red,
# the second sub-branch in orange and the second branch in blue
hc[[1]][[1]] = dendrapply(hc[[1]][[1]], colbranches, "red")
hc[[1]][[2]] = dendrapply(hc[[1]][[2]], colbranches, "orange")
hc[[2]] = dendrapply(hc[[2]], colbranches, "blue")

# Plot
plot(hc)

这使:

Answer 3

FigTree可以制作彩色树状图。例如，参见本文。

要将数据从 R 距离矩阵获取到FigTree dm，

library(ape)
z <- as.phylo(hclust(as.dist(dm)))
write.nexus(z, file="output.nex")