我想知道CompositeView是否/如何将数据传递到其定义的itemView.示例(简化)代码:
var TableView = Backbone.Marionette.CompositeView.extend({
template: '#table-template',
itemView: TableRowView,
itemViewContainer: 'tbody',
});
var TableRowView = Backbone.Marionette.ItemView.extend({
tagName: 'tr',
template: '#table-row-template',
serializeData: function () {
var data = {
model: this.model,
// FIXME This should really only be called once. Pass into TableView, and down into TableRowView?
// That way, getDisplayColumns can be moved to the collection as well, where it makes more sense for it to belong.
columns: this.model.getDisplayColumns()
};
return data;
}
});
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我正在使用这两个来呈现一个html表.#table-row-template有一些渲染逻辑,用于支持不同类型的"列".这允许我对不同类型的集合/模型使用相同的视图(只要它们遵循API).到目前为止,它运作良好!
但是,正如您在上面所看到的,每次"行"都会调用以获取相同的"列"数据,而实际上我只想将其传递一次,然后用于所有数据.
建议?
谢谢!
小智 14
您可以将itemViewOptions其用作对象或函数
var TableView = Backbone.Marionette.CompositeView.extend({
template: '#table-template',
itemView: TableRowView,
itemViewContainer: 'tbody',
itemViewOptions: {
columns: SOMEOBJECTORVALUE
}
});
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要么
var TableView = Backbone.Marionette.CompositeView.extend({
template: '#table-template',
itemView: TableRowView,
itemViewContainer: 'tbody',
itemViewOptions: function(model,index){
return{
columns: SOMEOBJECTORVALUE
}
}
});
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然后收到以下选项:
var TableRowView = Backbone.Marionette.ItemView.extend({
tagName: 'tr',
template: '#table-row-template',
initialize: function(options){
this.columns = options.columns;
}
});
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(*注意ItemView控件,itemViewContainer和itemViewOptions 2版本改变为childView,childViewContainer和childViewOptions).
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