如何在C#中将所有Excel工作表导入DataSet

Question

我已经在互联网上搜索了这个,并且找不到类似的问题.每个人都在寻找一种方法来导入excel文件中的单个工作表,但我想要的是DataTable在DataSet不知道工作表名称的情况下将文件中的所有工作表导入到.

我以前用Excel做过很多事情.这是我在互联网上找到的一个示例和部分工作代码,它只解析给定的工作表名称:

public static DataSet Parse(string fileName, string workSheetName)
{
    string connectionString = string.Format("provider=Microsoft.Jet.OLEDB.4.0; data source={0};Extended Properties=Excel 8.0;", fileName);
    string query = string.Format("SELECT * FROM [{0}$]", workSheetName);

    DataSet data = new DataSet();
    using (OleDbConnection con = new OleDbConnection(connectionString))
    {
        con.Open();
        OleDbDataAdapter adapter = new OleDbDataAdapter(query, con);
        adapter.Fill(data);
    }

    return data;
}

在上面的代码中,如您所见,应传入workSheetName,以便查询可以知道要导入的位置.就我而言,我希望它无论遍历所有的床单什么,他们被命名为喜欢和它们导入到个人DataTable的的DataSet.

所以从本质上讲,最后一件事就是DataSet在DataTable每个工作表中保存导入文件中每个工作表的行.

Answer 1

这是我提出的代码,它工作得很完美,但我看到其他人已经添加了答案:

static DataSet Parse(string fileName)
{
    string connectionString = string.Format("provider=Microsoft.Jet.OLEDB.4.0; data source={0};Extended Properties=Excel 8.0;", fileName);


    DataSet data = new DataSet();

    foreach(var sheetName in GetExcelSheetNames(connectionString))
    {
        using (OleDbConnection con = new OleDbConnection(connectionString))
        {    
            var dataTable = new DataTable();
            string query = string.Format("SELECT * FROM [{0}]", sheetName);
            con.Open();
            OleDbDataAdapter adapter = new OleDbDataAdapter(query, con);
            adapter.Fill(dataTable);
            data.Tables.Add(dataTable);
        }
    }

    return data;
}

static string[] GetExcelSheetNames(string connectionString)
{
        OleDbConnection con = null;
        DataTable dt = null;
        con= new OleDbConnection(connectionString);
        con.Open();
        dt = con.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, null);

        if (dt == null)
        {
            return null;
        }

        String[] excelSheetNames = new String[dt.Rows.Count];
        int i = 0;

        foreach (DataRow row in dt.Rows)
        {
            excelSheetNames[i] = row["TABLE_NAME"].ToString();
            i++;
        }

        return excelSheetNames;
}

Answer 2

因为我很无聊:

 static void Main(string[] args)
 {
            string filename = @"c:\temp\myfile.xlsx";    
            System.Data.OleDb.OleDbConnection myConnection = new System.Data.OleDb.OleDbConnection( 
                        "Provider=Microsoft.ACE.OLEDB.12.0; " +
                         "data source='" + filename + "';" +
                            "Extended Properties=\"Excel 12.0;HDR=YES;IMEX=1\" ");
            myConnection.Open();
            DataTable mySheets = myConnection.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, new object[] { null, null, null, "TABLE" });                
            DataSet ds = new DataSet();
            DataTable dt;

            for (int i = 0; i <= mySheets.Rows.Count; i++)
            {
                   dt =   makeDataTableFromSheetName(filename, mySheets.Rows[i]["TABLE_NAME"].ToString());
                   ds.Tables.Add(dt);
            }
 }

private static DataTable makeDataTableFromSheetName(string filename, string sheetName)
{      
    System.Data.OleDb.OleDbConnection myConnection = new System.Data.OleDb.OleDbConnection(
    "Provider=Microsoft.ACE.OLEDB.12.0; " +
    "data source='" + filename + "';" +
    "Extended Properties=\"Excel 12.0;HDR=YES;IMEX=1\" ");

    DataTable dtImport = new DataTable();
    System.Data.OleDb.OleDbDataAdapter myImportCommand = new System.Data.OleDb.OleDbDataAdapter("select * from [" + sheetName + "$]", myConnection);
    myImportCommand.Fill(dtImport);
    return dtImport;
}