Bil*_*ong 11 resources android identifier imageview viewflipper
我正在努力开发一款小游戏.
我有一个ViewFlipper,在ImageViews中有50张图片(4张图片的随机频率).然后我有4个按钮,相同的4张图片可以出现在ViewFlipper中.
任务是在出现右图时单击右键.(当显示图片1时,必须按下按钮1,依此类推)
我的问题是我不知道如何获取显示的ImageView ID.
flipper.getCurrentView().getId()
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给我"-1"作为Id.但我想拥有"R.drawable.pic1"的ID
我的代码到目前为止:
我的装载机方法:
protected void loadPicturesIntoFlipper() {
Random generator = new Random();
pictures = new ArrayList();
for(int i = 0; i < 50;i++){
int number = generator.nextInt(4) + 1;
if(number == 1){
pic = R.drawable.pic1;
}
if(number == 2){
pic = R.drawable.pic2;
}
if(number == 3){
pic = R.drawable.pic3;
}
if(number == 4){
pic = R.drawable.pic4;
}
pictures.add(pic);
}
for(int i=0;i<pictures.size();i++)
{
setFlipperImage((Integer) pictures.get(i));
}
}
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我的插入方法:
private void setFlipperImage(int res) {
image = new ImageView(getApplicationContext());
image.setBackgroundResource(res);
flipper.addView(image);
}
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我的检查方法:
protected void check(int number, int id) {
int code = 0;;
if(number == 1){
code = R.drawable.button_tip_finder;
}
if(number == 2){
code = R.drawable.button_about_us;
}
if(number == 3){
code = R.drawable.button_power_calculator;
}
if(number == 4){
code = R.drawable.button_powerpedia;
}
if(code == id){
test.setText(""+id);
}
else{
test.setText(""+id);
}
}
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我称之为:
button1.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
check(1,flipper.getCurrentView().getId());
flipper.showNext();
}
});
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M-W*_*eEh 14
像这样做:
private void setFlipperImage(int res) {
image = new ImageView(getContext());
image.setBackgroundResource(res);
image.setTag(res); //<------
flipper.addView(image);
}
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然后:
button1.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
check(1,(Integer)flipper.getCurrentView().getTag());//<----
flipper.showNext();
}
});
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else请在您的所有代码中使用BTW ,例如:
if(number == 1){
pic = R.drawable.pic1;
} else if(number == 2){
pic = R.drawable.pic2;
} else if(number == 3){
pic = R.drawable.pic3;
}
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