显示具有一对多关系的php mysql查询结果

Question

下面是一个样本表:

info table
info_id     name  
1           john  
2           peter
------------------------  
details table  
details_id      log                               date  
1            test log for john                  2013-08-01  
1            another log for john               2013-08-02  
2            test log for peter                 2013-08-02

这是我的示例查询:

SELECT info.info_id, info.name, details.details_no, details.log, details.date 
FROM info JOIN details ON details.details_id = info.info_id 
GROUP BY info.info_id  

这是我想要实现的显示:

john  
1     test log for john            2013-08-01  
1     another test log for john    2013-08-02  

peter  
2     test log for peter           213-08-02  

我尝试过使用foreach循环,然后在第一个循环中执行另一个foreach循环.

请帮助伙计们

Answer 1

尝试将结果制作成如下所示的多维数组

注意:我假设这details.details_no是details表的主键,并且您希望结果类似于

john  
1     test log for john            2013-08-01  
2     another test log for john    2013-08-02  

peter  
3     test log for peter           213-08-02

您可以使用以下内容检索

...
$qry = "
    SELECT
        info.info_id,
        info.name,
        details.details_no,
        details.log,
        details.date 
    FROM
        info
        JOIN details ON (details.details_id = info.info_id)
";
$result = mysqli_query($your_db_link,$qry)
$data = array();
while($row = mysqli_fetch_array($result)){
    $data[$row["info_id"]]["name"] = $row["name"];
    $data[$row["info_id"]]["logs"][$row["details_no"]] = array(
        "log"=>$row["log"],
        "date"=>$row["date"],
    );
}

会产生如下数组:

$data = array(
    "1" => array(
        "name" => "john",
        "logs" => array(
            "1" => array(
                "log" => "test log for john",
                "date" => "2013-08-01",
            ),
            "2" => array(
                "log" => "another test log for john",
                "date" => "2013-08-02",
            ),
        ),
    ),
    "2" => array(
        "name" => "peter",
        "logs" => array(
            "3" => array(
                "log" => "test log for peter",
                "date" => "2013-08-02",
            ),
        ),
    ),
);

然后你可以显示如下:

echo "<table>";
foreach($data as $value){
    echo "<tr><td colspan='3'>".$value["name"]."</td></tr>";
    foreach($value["logs"] as $subkey => $subvalue){
        echo "<tr>";
        echo "<td>".$subkey."</td>";
        echo "<td>".$subvalue["log"]."</td>";
        echo "<td>".$subvalue["date"]."</td>";
        echo "</tr>";
    }
}
echo "</table>";

这将导致类似于:

<table>
    <tr>
        <td colspan='3'>john</td>
    </tr>
    <tr>
        <td>1</td>
        <td>test log for john</td>
        <td>2013-08-01</td>
    </tr>
    <tr>
        <td>2</td>
        <td>another test log for john</td>
        <td>2013-08-02</td>
    </tr>
    <tr>
        <td colspan='3'>peter</td>
    </tr>
    <tr>
        <td>3</td>
        <td>test log for peter</td>
        <td>2013-08-02</td>
    </tr>
</table>