在C＃中创建类的对象时如何提高性能

Question

我知道这是一个愚蠢的问题，但我只想知道以下给定陈述中的区别：

Abc object= new ABC();
object.Age=obj1.Age;
object.Place=obj1.Place;
object.Street=obj1.Street;
object.Number=obj1.Number;
object.POBox=obj1.POBox;

和

Abc object= new ABC()
{
    Age=obj1.Age,
    Place=obj1.Place,
    Street=obj1.Street,
    Number=obj1.Number,
    POBox=obj1.POBox
};

以上编写的代码是否有助于提高性能？我只想知道在创建类的对象并将值分配给该类对象时，是否有任何方法可以提高性能？

Answer 1

否。这些语句被编译为相同的IL，因此不会提高性能。

第一个：

IL_0031: newobj instance void TestApplication.ABC::.ctor()
IL_0036: stloc.1
IL_0037: ldloc.1
IL_0038: ldc.i4.1
IL_0039: callvirt instance void TestApplication.ABC::set_Age(int32)
IL_003e: nop
IL_003f: ldloc.1
IL_0040: ldc.i4.1
IL_0041: callvirt instance void TestApplication.ABC::set_Place(int32)
IL_0046: nop
IL_0047: ldloc.1
IL_0048: ldc.i4.1
IL_0049: callvirt instance void TestApplication.ABC::set_Street(int32)
IL_004e: nop
IL_004f: ldloc.1
IL_0050: ldc.i4.1
IL_0051: callvirt instance void TestApplication.ABC::set_Number(int32)
IL_0056: nop
IL_0057: ldloc.1
IL_0058: ldc.i4.1
IL_0059: callvirt instance void TestApplication.ABC::set_POBox(int32)

第二个：

IL_0001: newobj instance void TestApplication.ABC::.ctor()
IL_0006: stloc.2
IL_0007: ldloc.2
IL_0008: ldc.i4.1
IL_0009: callvirt instance void TestApplication.ABC::set_Age(int32)
IL_000e: nop
IL_000f: ldloc.2
IL_0010: ldc.i4.1
IL_0011: callvirt instance void TestApplication.ABC::set_Place(int32)
IL_0016: nop
IL_0017: ldloc.2
IL_0018: ldc.i4.1
IL_0019: callvirt instance void TestApplication.ABC::set_Street(int32)
IL_001e: nop
IL_001f: ldloc.2
IL_0020: ldc.i4.1
IL_0021: callvirt instance void TestApplication.ABC::set_Number(int32)
IL_0026: nop
IL_0027: ldloc.2
IL_0028: ldc.i4.1
IL_0029: callvirt instance void TestApplication.ABC::set_POBox(int32)