使用XmlSerializer忽略.NET中Xml序列化中属性的属性

Question

我正在使用Xml进行血清化XmlSerializer.我正在执行序列化ClassA,其中包含名为MyPropertytype的属性ClassB.我不希望ClassB序列化特定属性.

我必须使用,XmlAttributeOverrides因为这些类在另一个库中.如果财产ClassA本身,它将是直截了当的.

XmlAttributeOverrides xmlOver = new XmlAttributeOverrides();
XmlAttributes xmlAttr = new XmlAttributes();
xmlAttr.XmlIgnore = true;
xmlOver.Add(typeof(ClassA), "MyProperty", xmlAttr);

XmlSerializer ser = new XmlSerializer(typeof(ClassA), xmlOver);

如果属性在ClassB,我们需要序列化如何完成ClassA？

Answer 1

你几乎得到它,只需更新你的覆盖指向ClassB而不是ClassA:

XmlAttributeOverrides xmlOver = new XmlAttributeOverrides();
XmlAttributes xmlAttr = new XmlAttributes();
xmlAttr.XmlIgnore = true;

//change this to point to ClassB's property to ignore
xmlOver.Add(typeof(ClassB), "ThePropertyNameToIgnore", xmlAttr);

XmlSerializer ser = new XmlSerializer(typeof(ClassA), xmlOver);

快速测试,给出:

public class ClassA
{
    public ClassB MyProperty { get; set; }
}

public class ClassB
{
    public string ThePropertyNameToIgnore { get; set; }
    public string Prop2 { get; set; }
}

和出口方式:

public static string ToXml(object obj)
{
    XmlAttributeOverrides xmlOver = new XmlAttributeOverrides();
    XmlAttributes xmlAttr = new XmlAttributes();
    xmlAttr.XmlIgnore = true;
    xmlOver.Add(typeof(ClassB), "ThePropertyNameToIgnore", xmlAttr);


    XmlSerializer xs = new XmlSerializer(typeof(ClassA), xmlOver);
    using (MemoryStream stream = new MemoryStream())
    {
        xs.Serialize(stream, obj);
        return System.Text.Encoding.UTF8.GetString(stream.ToArray());
    }
}

主要方法:

void Main()
{
    var classA = new ClassA {
        MyProperty = new ClassB {
            ThePropertyNameToIgnore = "Hello",
            Prop2 = "World!"
        }
    };

    Console.WriteLine(ToXml(classA));
}

通过省略"ThePropertyNameToIgnore"输出

<?xml version="1.0"?>
<ClassA xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <MyProperty>
    <Prop2>World!</Prop2>
  </MyProperty>
</ClassA>