每天两次之间的时间

Question

我已经尝试过NSDate,但没有运气.我想要例如14:10和18:30之间的区别.

小时和分钟.

我希望你能帮助我不要那么复杂:)

Answer 1

没有必要手动计算,看一看NSCalendar.如果您想获得两个日期之间的小时和分钟,请使用以下内容:

NSCalendar *gregorianCalendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSUInteger unitFlags = NSHourCalendarUnit | NSMinuteCalendarUnit;
NSDateComponents *components = [gregorianCalendar components:unitFlags
                                                    fromDate:firstDate
                                                      toDate:otherDate
                                                     options:0];
[gregorianCalendar release];

您现在有小时和分钟为NSDateComponents并且可以访问他们的NSIntegers喜欢[components hour]和[components minute].这也可以在几天,闰年和其他有趣的东西之间工作几个小时.

Answer 2

这是我的快速解决方案:

NSDateFormatter *df = [[[NSDateFormatter alloc] init] autorelease];
[df setDateFormat:@"HH:mm"];
NSDate *date1 = [df dateFromString:@"14:10"];
NSDate *date2 = [df dateFromString:@"18:09"];
NSTimeInterval interval = [date2 timeIntervalSinceDate:date1];
int hours = (int)interval / 3600;             // integer division to get the hours part
int minutes = (interval - (hours*3600)) / 60; // interval minus hours part (in seconds) divided by 60 yields minutes
NSString *timeDiff = [NSString stringWithFormat:@"%d:%02d", hours, minutes];

Answer 3

NSDate类有一个方法timeIntervalSinceDate来完成这个技巧.

NSTimeInterval secondsBetween = [firstDate timeIntervalSinceDate:secondDate];

NSTimeInterval是一个double,表示两次之间的秒数.

Answer 4

NSString *duration = [self calculateDuration:oldTime secondDate:currentTime];

- (NSString *)calculateDuration:(NSDate *)oldTime secondDate:(NSDate *)currentTime
{
    NSDate *date1 = oldTime;
    NSDate *date2 = currentTime;

    NSTimeInterval secondsBetween = [date2 timeIntervalSinceDate:date1];

    int hh = secondsBetween / (60*60);
    double rem = fmod(secondsBetween, (60*60));
    int mm = rem / 60;
    rem = fmod(rem, 60);
    int ss = rem;

    NSString *str = [NSString stringWithFormat:@"%02d:%02d:%02d",hh,mm,ss];

    return str;
}