在字典<string,<IEnumerable string >>中连接键和值以生成一个列表

Question

我有

Dictionary<string,IEnumerable<string>> pathAndItems = new Dictionary<string,IEnumerable<String>>();

如

this/is/path/: {hey, ho, lets, go}
another/path/: {hey, hello}

我想要做的是使用所有连接的值制作一个IEnumerable.

this/is/path/hey, this/is/path/ho, this/is/path/lets, this/is/path/go, another/path/hey, another/path/hello

我可以把所有这些都集中在一起,但我怎样才能将密钥添加到每个密钥中？

var SL_requirements = SL_requirementsDict.SelectMany(kvp => kvp.Value);

编辑:我想将它作为LINQ表达式而不是循环

Answer 1

有各种剥皮方法.SelectMany还允许您(source, projected-element)在查询表达式中指定对每个对执行的操作:

var query = from pair in dictionary
            from value in pair.Value
            select pair.Key + "/" + value;

或者用点符号表示:

var query = dictionary.SelectMany(kvp => kvp.Value,
                                  (kvp, value) => kvp.Key + "/" + value);