我正在查看本书中提供的示例代码
enum Coin
{
PENNY(1),
NICKEL(5),
DIME(10),
QUARTER(25);
private final int denomValue;
Coin(int denomValue)
{
this.denomValue = denomValue;
}
int denomValue()
{
return denomValue;
}
int toDenomination(int numPennies)
{
return numPennies / denomValue;
}
}
public class Coins
{
public static void main(String[] args)
{
if (args.length == 1)
{
int numPennies = Integer.parseInt(args[0]);
System.out.println(numPennies + " pennies is equivalent to:");
int numQuarters = Coin.QUARTER.toDenomination(numPennies);
System.out.println(numQuarters + " " + Coin.QUARTER.toString() +
(numQuarters != 1 ? "s," : ","));
numPennies -= numQuarters * Coin.QUARTER.denomValue();
int numDimes = Coin.DIME.toDenomination(numPennies);
System.out.println(numDimes + " " + Coin.DIME.toString() +
(numDimes != 1 ? "s, " : ","));
numPennies -= numDimes * Coin.DIME.denomValue();
int numNickels = Coin.NICKEL.toDenomination(numPennies);
System.out.println(numNickels + " " + Coin.NICKEL.toString() +
(numNickels != 1 ? "s, " : ", and"));
numPennies -= numNickels*Coin.NICKEL.denomValue();
System.out.println(numPennies + " " + Coin.PENNY.toString() +
(numPennies != 1 ? "s" : ""));
}
System.out.println();
System.out.println("Denomination values:");
for (int i = 0; i < Coin.values().length; i++)
System.out.println(Coin.values()[i].denomValue());
}
}
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如果enum就像一个类,是否可以为类中的方法和字段使用相同的名称,因为这里使用denomValue完成了?
为什么这样打电话int numQuarters = Coin.QUARTER.toDenomination(numPennies);?toDenomination()默认是静态的吗?
在上面的例子中,denomValue字段的值是多少?该程序的输出提示它应该等于QUARTER.但是这有什么作用呢?Coin.QUARTER相当于创建一个硬币对象并传递QUARTER作为它的构造函数参数吗?
每一个PENNY,NICKEL都是实例Coin类是静态的,所以它们可以作为进行访问Coin.PENNY.
所以当你这样做时:
Coin.QUARTER.toDenomination(numPennies)
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您正在访问QUARTERcoin类的实例并调用其toDenomination()方法,该方法是在实例上调用的实例方法QUARTER.
当你这样做时:
PENNY(1) //this actually calls the constructor with one integer argument of Coin class
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要检查PENNY是否是Coin类的实例:
System.out.println(Coin.PENNY.getClass()); //Will show you Coin
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