HP.*_*HP. 10 javascript web-crawler node.js phantomjs casperjs
我有以下简单的代码:
var casper = require("casper").create({
}),
utils = require('utils'),
http = require('http'),
fs = require('fs');
casper.start();
casper.thenOpen('http://www.yahoo.com/', function() {
casper.capture('test.png');
});
casper.on('http.status.404', function(resource) {
this.echo('wait, this url is 404: ' + resource.url);
});
casper.run(function() {
casper.exit();
});
Run Code Online (Sandbox Code Playgroud)
有没有办法捕捉http.status代码而不管它是什么?现在我可以在doc中看到显示捕获特定代码事件的方法.如果我只想看看它是什么怎么办?
tht*_*gma 11
怎么样(来自Docs):
var casper = require("casper").create({
}),
utils = require('utils'),
http = require('http'),
fs = require('fs');
casper.start();
casper.thenOpen('http://www.yahoo.com/', function(response) {
casper.capture('test.png');
utils.dump(response.status);
if (response == undefined || response.status >= 400) this.echo("failed");
});
casper.on('http.status.404', function(resource) {
this.echo('wait, this url is 404: ' + resource.url);
});
casper.run(function() {
casper.exit();
});
Run Code Online (Sandbox Code Playgroud)