IndexError：元组索引超出范围

Question

我指的是django文档的这一页来编写视图。有人可以解释我做错了什么吗？那可能是解决方案

    self.object_list = self.get_queryset()
  File "/vagrant/projects/kodeworms/course/views.py", line 23, in get_queryset
    self.Course = get_object_or_404(Course, name=self.args[0])
  IndexError: tuple index out of range

我的views.py文件

# Create your views here.
from django.views.generic import ListView, DetailView
from django.shortcuts import get_object_or_404

from .models import Course, Content


class PublishedCourseMixin(object):
    def get_queryset(self):
        queryset = super(PublishedCourseMixin, self).get_queryset()
        return queryset.filter(published_course=True)


class CourseListView(PublishedCourseMixin, ListView):
    model = Course
    template_name = 'course/course_list.html'

class CourseContentListView(ListView):
    model = Content
    template_name = 'course/content_list.html'

    def get_queryset(self):
        self.Course = get_object_or_404(Course, name=self.args[0])
        return Content.objects.filter(course=self.course, published=True)

我的urls.py文件

from django.conf.urls import patterns, url

from . import views

urlpatterns = patterns('',
    url(r"^$", views.CourseListView.as_view(), name="list" ),
    url(r"^(?P<slug_topic_name>[\w-]+)/$", views.CourseContentListView.as_view(), name="list"),
)

Answer 1

您使用的self.args[0]是位置参数，但是您正在将关键字参数传递给视图。

由于您没有位置参数 self.args是一个零长度的元组，这就是为什么您会收到该异常的原因。

您应该使用，self.kwargs['slug_topic_name']因为您的网址中包含关键字参数。