MD *_*AIN 3 javascript jquery html5 html5-canvas
这是jsfiddle
我有这个作为我的源画布
HTML
<h1>Source Canvas</h1>
<canvas id="source" width=436 height=567></canvas>
<h1>Destination Canvas</h1>
<canvas id="destination" width=436 height=567></canvas>
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JavaScript的
var sourceImage, ctx, sourceCanvas, destinationCanvas;
//get the canvases
sourceCanvas = document.getElementById('source');
destinationCanvas = document.getElementById('destination');
//draw the source image to the source canvas
ctx = sourceCanvas.getContext('2d');
function start() {
ctx.drawImage(img1, 0, 0);
ctx.globalCompositeOperation = "source-atop";
var pattern = ctx.createPattern(img, 'repeat');
ctx.rect(0, 0, sourceCanvas.width, sourceCanvas.height);
ctx.fillStyle = pattern;
ctx.fill();
ctx.globalAlpha = .10;
ctx.drawImage(img1, 0, 0);
ctx.drawImage(img1, 0, 0);
ctx.drawImage(img1, 0, 0);
//ctx.globalAlpha = 1;
}
var img1 = new Image();
var img = new Image();
img.onload = function () {
img1.onload = function () {
start();
}
img1.src = "https://dl.dropboxusercontent.com/u/139992952/stackoverflow/4jiSz1.png";
}
img.src = "https://dl.dropboxusercontent.com/u/139992952/stackoverflow/BooMu1.png";
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我想在我的目标画布中显示源画布中的内容.
我累了
var image, destinationCtx;
//create the image
image = new Image();
//get the base64 data
image.src = sourceCanvas.toDataURL('image/png');
//get the destination context
destinationCtx = destinationCanvas.getContext('2d');
//copy the data
destinationCtx.drawImage(image, 0, 0);
//done
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但没有运气.我错过了什么吗?通过imageData复制,通过Base64数据复制,通过直接绘制复制任何方法都可以完成我的工作.当我尝试
http://jsperf.com/copying-a-canvas-element 它复制但是当我把我的源画布编写器它不起作用?我错过了什么吗?
您可以直接将一个画布复制到其他画布上 像这样...
var destinationCtx;
//get the destination context
destinationCtx = destinationCanvas.getContext('2d');
//copy the data
destinationCtx.drawImage(sourceCanvas, 0, 0);
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