这是我正在使用的代码
$Last_Video = $db->fetch_all('
SELECT VID, thumb
FROM video
WHERE VID IN (
SELECT VID
FROM video
WHERE title LIKE "%'.$Channel['name'].'%"
ORDER BY viewtime DESC
LIMIT 5)
ORDER BY RAND()
LIMIT 1
');
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这是给我的错误
Message: Error during SQL execution: SELECT VID, thumb FROM video WHERE VID IN ( SELECT VID FROM video WHERE title LIKE "%funny%" ORDER BY viewtime DESC LIMIT 5) ORDER BY RAND() LIMIT 1<br />
MySQL Error: This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'<br />
MySQL Errno: 1235
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我怎么能解决这个问题?它的其他方式...所以我没有得到错误...
Mik*_*ant 135
您可以使用JOIN而不是IN
SELECT v.VID, v.thumb
FROM video AS v
INNER JOIN
(SELECT VID
FROM video
WHERE title LIKE "%'.$Channel['name'].'%"
ORDER BY viewtime DESC
LIMIT 5) as v2
ON v.VID = v2.VID
ORDER BY RAND()
LIMIT 1
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小智 119
您可以使用以下方法绕过此错误.
$Last_Video = $db->fetch_all('
SELECT VID, thumb
FROM video
WHERE VID IN (select * from (
SELECT VID
FROM video
WHERE title LIKE "%'.$Channel['name'].'%"
ORDER BY viewtime DESC
LIMIT 5) temp_tab)
ORDER BY RAND()
LIMIT 1
');
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这里不需要子查询.试试这个:
SELECT VID, thumb
FROM video
WHERE title LIKE "%'.$Channel['name'].'%"
ORDER BY RAND() DESC
LIMIT 1
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在MySQL 5.0.26及更高版本中,您将收到错误:
对于某些子查询运算符,MySQL不支持子查询中的LIMIT:
参考.
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