CMH*_*CMH 8 javascript sorting algorithm function
我有一个阵列.该数组可以包含1到7个唯一的日期名称字符串.当天的名字将从周一到周日. - 例如:
["星期二","星期四","太阳报"]
我想使用javascript对该数组进行排序,以便订单将从今天开始.
即:如果今天是星期五,那么排序的数组应该是
["太阳报","星期二","星期四"]
如果今天是星期四那么排序的数组应该是
["星期四","太阳报","星期二"]
有人可以帮忙吗?
function sort_days(days) {
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要获得今天的一周,请使用new Date().getDay().这假定Sunday = 0, Monday = 1, ..., Saturday = 6.
var day_of_week = new Date().getDay();
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要生成星期几的列表,请切片名称列表:
var list = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"];
var sorted_list = list.slice(day_of_week).concat(list.slice(0,day_of_week));
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(今天是星期五,所以sorted_list是['Fri','Sat','Sun','Mon','Tue','Wed','Thu'])
最后,要排序,使用indexOf:
return days.sort(function(a,b) { return sorted_list.indexOf(a) > sorted_list.indexOf(b); });
}
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把它们放在一起:
function sort_days(days) {
var day_of_week = new Date().getDay();
var list = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"];
var sorted_list = list.slice(day_of_week).concat(list.slice(0,day_of_week));
return days.sort(function(a,b) { return sorted_list.indexOf(a) > sorted_list.indexOf(b); });
}
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这是我想出的一个函数:
function sortDays(days) {
var daysOfWeek = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"];
var today = new Date().getDay();
for (var i=0;i<today;i++) daysOfWeek.push(daysOfWeek.shift());
return daysOfWeek.filter(function(d) { return days.indexOf(d) >= 0; });
}
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总体思路是根据今天是哪一天,通过从开始到结束轮换元素来重新安排一周中的几天。然后,您使用该排序重新排序您的输入数组以匹配。我没有实际排序,而是daysOfWeek根据输入数组的内容过滤数组。
我不确定Array.filter支持的程度,因此您可能希望将其更改为通用 for 循环,而不是取决于您要支持的浏览器。
这是一个 jsfiddle,您也可以在其中使用它。
或者,您可以Array.sort按照类似的策略使用内置方法:
var daysOfWeek = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"];
{
var today = new Date().getDay();
for (var i=0;i<today;i++) daysOfWeek.push(daysOfWeek.shift());
}
function daysOfWeekSorter(x,y) {
return daysOfWeek.indexOf(x)-daysOfWeek.indexOf(y);
}
var myDays = ["Tue", "Thu", "Sun"];
myDays.sort(daysOfWeekSorter);
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而这里的另一个拨弄一起玩。
const days = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"];
const sortDays = function (a, b) {
a = days.indexOf(a);
b = days.indexOf(b);
return a < b ? 0 : 1;
};
const myArrayOfDays = ["Tuesday", "Saturday", "Monday", "Thursday"].sort(sortDays);
// returns ["Monday", "Tuesday", "Thursday", "Saturday"];
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