Jåc*_*cob 30 spring hibernate jpa jpa-2.0
这篇文章是继续JPA如何在持久化后从数据库中获取值
当我执行以下操作时,我遇到以下异常,我该如何解决?
Not allowed to create transaction on shared EntityManager - use Spring
transactions or EJB CMT
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DAOImpl代码
public void create(Project project) {
entityManager.persist(project);
entityManager.getTransaction().commit();
project = entityManager.find(Project.class, project.getProjectId());
entityManager.refresh(project);
System.out.println("Id -- " + project.getProjectId());
System.out.println("no -- " + project.getProjectNo());
}
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applicationContext.xml中
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<bean id="DataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="username" value="scott" />
<property name="password" value="tiger" />
<property name="driverClassName" value="oracle.jdbc.driver.OracleDriver" />
<property name="url" value="jdbc:oracle:thin:@myserver:1521:ORCL" />
</bean>
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="DataSource" />
<property name="packagesToScan" value="test.entity" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true" />
<property name="generateDdl" value="false" />
<property name="databasePlatform" value="org.hibernate.dialect.Oracle10gDialect" />
</bean>
</property>
</bean>
<context:component-scan base-package="test.net" />
<tx:annotation-driven transaction-manager="transactionManager"/>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<context:annotation-config/>
</beans>
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小智 40
我想这里的问题是虽然你已经为事务管理器定义了bean,但你还没有注释create()方法,@Transactional
它启用了spring事务.
同样删除entityManager.getTransaction().commit();
语句,因为现在所有的事务管理都将由spring处理,如果你保留语句,那么你将再次得到相同的错误.
小智 9
entityManager.getTransaction().begin() and annotate the method using
您需要删除@Transactional语句吗?这使得 Spring 能够进行事务处理。
在方法上注入EntityManagerFactory而不是EntityManager和javax.transaction.Transactional注释解决了我的问题,如下所示。
//Autowire EntityManagerFactory
@PersistenceUnit(unitName = "readwrite.config")
private EntityManagerFactory entityManagerFactory;
//Use below code on create/update
EntityManager entityManager = entityManagerFactory.createEntityManager();
entityManager.getTransaction().begin();
if (!ObjectUtils.isEmpty(entity) && !entityManager.contains(entity)) {
entityManager.persist(entity);
entityManager.flush();
}
entityManager.getTransaction().commit();
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