Mongoid:和 - 或查询

Question

我有这个问题:

User.or( { name: 'John' }, { name: 'Sara' } ).or( { age: 17 }, { age: 18 } ) )

它返回下一个标准:

#<Mongoid::Criteria
  selector: {"enabled"=>true, "$or"=>[{"name"=>"John"}, {"name"=>"Anoun"}, {"age"=>17}. {"age"=>18}]}
  options:  {}
  class:    User
  embedded: false>

但我想做'和'两个'或'返回这样的东西:

#<Mongoid::Criteria
  selector: {"enabled"=>true, "$and"=>[
    {"$or"=>[{"name"=>"John"}, {"name"=>"Anoun"}]}, 
    {"$or"=>[{"age"=>17}, {"age"=>18}]}
  ] }
  options:  {}
  class:    User
  embedded: false>

怎么会是查询？

Answer 1

这可能对你有帮助,

User.where(enabled: true)
    .and( 
          User.or( { name: 'John' }, { name: 'Sara' } ).selector,
          User.or( { age: 17 }, { age: 18 } ).selector
        )

这将返回:

#<Mongoid::Criteria
  selector: {"enabled"=>true, "$and"=>[{"$or"=>[{"name"=>"John"}, {"name"=>"Sara"}]}, {"$or"=>[{"age"=>17}, {"age"=>18}]}]}
  options:  {}
  class:    User
  embedded: false>

Answer 2

您不需要链接$或查询 - 您只需要名称在列表中的文档,以及年龄在列表中的位置.Mongo很容易提供:

db.users.find({enabled: true, name: {$in: ["John", "Sara"]}, age: {$in: [17, 18]}})

用Mongoid的说法,这很简单:

User.where(enabled: true, name.in: ["John", "Sara"], age.in: [17, 18])