PostgreSQL-动态创建数据库和表

Question

该代码不起作用。谁能指导我在哪里可以找到使用C＃快速创建Postgresql数据库和表的示例？

     const string connStr = "Server=localhost;Port=5432;
                          User Id=postgres;Password=enter;Database=postgres";

        var m_conn = new NpgsqlConnection(connStr);

        // creating a database in Postgresql
        m_createdb_cmd = new NpgsqlCommand("CREATE DATABASE IF NOT EXISTS  \"testDb\" " +
                                       "WITH OWNER = \"postgres\" " +
                                       "ENCODING = 'UTF8' " +
                                       "CONNECTION LIMIT = -1;", m_conn);

        // creating a table in Postgresql
        m_createtbl_cmd = new NpgsqlCommand(
            "CREATE TABLE MyTable(CompanyName VARCHAR(150))";

        m_conn.Open();
        m_createdb_cmd.ExecuteNonQuery();
        m_createtbl_cmd.Connection = m_conn;
        m_conn.Close();

数据库已创建，但是在创建表时出现静默失败。

Answer 1

我会这样做：

string connStr = "Server=localhost;Port=5432;User Id=postgres;Password=enter;";
var m_conn = new NpgsqlConnection(connStr);
var m_createdb_cmd = new NpgsqlCommand(@"
    CREATE DATABASE IF NOT EXISTS testDb
    WITH OWNER = postgres
    ENCODING = 'UTF8'
    CONNECTION LIMIT = -1;
    ", m_conn);
m_conn.Open();
m_createdb_cmd.ExecuteNonQuery();
m_conn.Close();

connStr = "Server=localhost;Port=5432;User Id=postgres;Password=enter;Database=testDb";
m_conn = new NpgsqlConnection(connStr);
m_createtbl_cmd = new NpgsqlCommand(
   "CREATE TABLE table1(ID CHAR(256) CONSTRAINT id PRIMARY KEY, Title CHAR)"
   , m_conn);
m_conn.Open();
m_createtbl_cmd.ExecuteNonQuery();
m_conn.Close();

采用var不建议在这里。我使用它是因为我不知道返回的类型是什么，但是您应该这样做。

注意使用原始字符串（@）。它使字符串构建变得简单。

除非标识符是非法的，否则不要在Postgresql中使用双引号括起来的标识符。这会使您的生活更加艰难。

Answer 2

解决方案：

    // 1. Connect to server to create database:
    const string connStr = "Server=localhost;Port=5432;User Id=postgres;Password=enter;";

    // 2. Connect to server to create table:
    const string connStr2 = "Server=localhost;Port=5432;User Id=postgres;Password=enter;Database=testDb";


    var m_conn = new NpgsqlConnection(connStr); // db connction
    var m_conn2 = new NpgsqlConnection(connStr2); // table connection

    // creating a database in Postgresql
    m_createdb_cmd = new NpgsqlCommand("CREATE DATABASE IF NOT EXISTS  \"testDb\" " +
                                   "WITH OWNER = \"postgres\" " +
                                   "ENCODING = 'UTF8' " +
                                   "CONNECTION LIMIT = -1;", m_conn);

    // creating a table in Postgresql
    m_createtbl_cmd = new NpgsqlCommand
       {
       CommandText ="CREATE TABLE table1(ID CHAR(256) CONSTRAINT id PRIMARY KEY, Title CHAR)"
       };

       m_createtbl_cmd.Connection = m_conn2;

 // 3.. Make connection and create

        // open connection to create DB
        m_conn.Open();
        m_createdb_cmd.ExecuteNonQuery();
        m_conn.Close();

        // open connection to create table
        m_conn2.Open();
        m_createtbl_cmd.ExecuteNonQuery();
        m_conn2.Close();

这可行，但是有没有更短的方法来做到这一点？我必须创建两个 Npgsql 连接。我不知道，只是对我来说看起来不太优雅。