Tab*_*Tab 8 reverse-geocoding google-maps-api-3
我使用谷歌地图api 3从坐标获取城市.我阅读了ReverseGeocoding,但我不明白如何从这种类型的结果中获得正确的城市价值:http://maps.googleapis.com/maps/api/geocode/json ?latlng = 40.714224,-73.961452&theseor = false
de_*_*uit 17
此Funktion以纬度/经度返回所请求城市的名称.因为这个脚本是从2012年底开始的.那个时候我的工作很好.当API找不到时返回"unknown".
function get_api ($lat, $long) {
$get_API = "http://maps.googleapis.com/maps/api/geocode/json?latlng=";
$get_API .= round($lat,2).",";
$get_API .= round($long,2);
$jsonfile = file_get_contents($get_API.'&sensor=false');
$jsonarray = json_decode($jsonfile);
if (isset($jsonarray->results[1]->address_components[1]->long_name)) {
return($jsonarray->results[1]->address_components[1]->long_name);
}
else {
return('Unknown');
}
}
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编辑:和一个jquery.
<p id="city"></p>
<script>
$(document).ready( function () {
// define lat / long
var lat = 37.42;
var long = -122.08;
$.ajax({
type: 'GET',
dataType: "json",
url: "http://maps.googleapis.com/maps/api/geocode/json?latlng="+lat+","+long+"&sensor=false",
data: {},
success: function(data) {
$('#city').html(data);
$.each( data['results'],function(i, val) {
$.each( val['address_components'],function(i, val) {
if (val['types'] == "locality,political") {
if (val['long_name']!="") {
$('#city').html(val['long_name']);
}
else {
$('#city').html("unknown");
}
console.log(i+", " + val['long_name']);
console.log(i+", " + val['types']);
}
});
});
console.log('Success');
},
error: function () { console.log('error'); }
});
});
</script>
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在 HTML5 页面中,我们可以按如下方式获取城市名称:
<script src="//maps.googleapis.com/maps/api/js?v=3.exp&sensor=true"></script>
<script>
(function() {
if(!!navigator.geolocation) {
navigator.geolocation.getCurrentPosition(function(position) {
var geocoder = new google.maps.Geocoder();
var geolocate = new google.maps.LatLng(position.coords.latitude, position.coords.longitude);
console.log(position.coords.latitude + ', ' + position.coords.longitude);
geocoder.geocode({'latLng': geolocate}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
var result;
if (results.length > 1) {
result = results[1];
} else {
result = results[0];
}
//console.log(result);
console.log(result.address_components[2].long_name + ', ' + result.address_components[3].long_name);
}
});
});
</script>
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