我正在学习R,我很好奇......我需要一个能够做到这一点的功能:
> fillInTheBlanks(c(1, NA, NA, 2, 3, NA, 4))
[1] 1 1 1 2 3 3 4
> fillInTheBlanks(c(1, 2, 3, 4))
[1] 1 2 3 4
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我制作了这个......但我怀疑还有更多的R方法可以做到这一点.
fillInTheBlanks <- function(v) {
## replace each NA with the latest preceding available value
orig <- v
result <- v
for(i in 1:length(v)) {
value <- v[i]
if (!is.na(value))
result[i:length(v)] <- value
}
return(result)
}
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rcs*_*rcs 14
套餐zoo
有一个功能na.locf()
:
R> library("zoo")
R> na.locf(c(1, 2, 3, 4))
[1] 1 2 3 4
R> na.locf(c(1, NA, NA, 2, 3, NA, 4))
[1] 1 1 1 2 3 3 4
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na.locf
:最后的观察结果; 用于在每个'NA'之前替换最近的非'NA'的通用函数.
查看函数的源代码na.locf.default
,它不需要for
-loop.
mar*_*omo 13
我正在从动物园图书馆做一些最小的复制和粘贴(再次感谢rcs指点我)这就是我真正需要的:
fillInTheBlanks <- function(S) {
## NA in S are replaced with observed values
## accepts a vector possibly holding NA values and returns a vector
## where all observed values are carried forward and the first is
## also carried backward. cfr na.locf from zoo library.
L <- !is.na(S)
c(S[L][1], S[L])[cumsum(L)+1]
}
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