警告:mysqli_fetch_assoc()期望参数1是mysqli_result,给出的数组

Question

我收到此错误"警告:mysqli_fetch_assoc()预计参数1被mysqli_result,阵中给出"出的代码片断"searchcar.php"的

$modelmake = $_POST['model_make'];
$result = $db->select('car_information','*', 'Model_Make LIKE \'%$modelmake%\''); 
while($row = mysqli_fetch_assoc($result))
{
    echo 'Model'.$row['model_make'];
}

这是来自"database.php"的select函数的代码片段

 public function select(
        $table,
        $fields = '*',
        $where = '1=1',
        $order = '',
        $limit = '',
        $desc = false,
        $limitBegin = 0,
        $groupby = null,
        $monitoring = false
    ) //monitoring is set to true to view the actual query
    {
//  $query ='SELECT ' . $fields . ' FROM ' . $table ;
    $query = 'SELECT ' . $fields . ' FROM ' . $table . ' WHERE ' . $where;

        if (!empty($groupby)) {
            $query .= ' GROUP BY ' . $groupby;
        }

        if (!empty($order)) 
        {
            $query .= ' ORDER BY ' . $order;

            if ($desc) 
            {
                $query .= ' DESC';
            }
        }

        if (!empty($limit))
        {
            $query .= ' LIMIT ' . $limitBegin . ', ' . $limit;
        }

        $result = $this->_sendQuery($query);

        $resultArray = array();

        while ($row = mysqli_fetch_assoc($result)) 
        {
            $resultArray[] = $row;
        }

        if ($monitoring) 
        {       
            // If monitoring is activated, echo the query
            echo $query;
        }
        return $resultArray;
    }    

我想用这行"while($ row = mysqli_fetch_assoc($ result))"请指教!

Answer 1

你的select方法是返回一个array,而不是一个resource.这意味着mysqli_fetch_assoc抱怨是对的.

好消息是该select方法返回一个结果数组,这意味着您可以替换while($row = mysqli_fetch_assoc($result))为

foreach($result as $row)