使用MATLAB获取信号的包络

Question

我正在尝试提取音频文件的峰值.我有以下代码来提取振幅谱的包络.但是我没有得到所需的输出图.有人可以告诉我需要做些什么调整来获得正确的图表.这是我的代码:

[song,FS] = wavread('c scale fast.wav');


P=20000/44100*FS;                   % length of filter 
N=length(song);                     % length of song
t=0:1/FS:(N-1)/FS;                  % define time period
% Plot time domain signal
figure(1);
subplot(3,1,1)
plot(t,(3*abs(song)))
title('Wave File')
ylabel('Amplitude')
xlabel('Length (in seconds)')
xlim([0 1.1])

xlim([0 N/FS])


% Gaussian Filter
x = linspace( -1, 1, P);         % create a vector of P values between -1 and 1 inclusive
sigma = 0.335;                  % standard deviation used in Gaussian formula
myFilter = -x .* exp( -(x.^2)/(2*sigma.^2));% compute first derivative, but leave constants out

myFilter = myFilter / sum( abs( myFilter ) ); % normalize
% Plot Gaussian Filter

subplot(3,1,2)       
plot(myFilter)
title('Edge Detection Filter')

% fft convolution
myFilter = myFilter(:);                         % create a column vector
song(length(song)+length(myFilter)-1) = 0;      %zero pad song
myFilter(length(song)) = 0;                     %zero pad myFilter
edges =ifft(fft(song).*fft(myFilter));

tedges=edges(P/2:N+P/2-1);                      % shift by P/2 so peaks line up w/ edges
tedges=tedges/max(abs(tedges));                 % normalize

% Plot song filtered with edge detector          
subplot(3,1,3)

plot(1/FS:1/FS:N/FS,tedges)
title('Song Filtered With Edge Detector')
xlabel('Time (s)')
ylabel('Amplitude')
ylim([-1 1.1])
xlim([0 N/FS])

这是我获得上述代码的图表,我专注于"用边缘检测器过滤的歌曲"图

这是我需要得到的"用边缘检测器过滤的歌曲"的情节

Answer 1

您可以使用希尔伯特变换来获取包络.从技术上讲,这会返回分析信号.您将获得包含以下行的信封:

envelope = abs(hilbert(Song));

希尔伯特变换的作用是取fft输入,将负频率归零,然后进行ifft.变换的实部是原始信号,虚部是变换后的信号.实部和虚部的绝对值是包络,而参数(angle(hilbert(Song)))是瞬时相位.