Har*_*rry 1 python string io dictionary list
我正在试图弄清楚如何打开一个文件,然后使用Part no将它的内容存储到字典中.作为关键和其他信息作为价值.所以我希望它看起来像这样:
{Part no.: "Description,Price", 453: "Sperving_Bearing,9900", 1342: "Panametric_Fan,23400",9480: "Converter_Exchange,93859"}
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我能够将文件中的文本存储到列表中,但我不确定如何为一个键分配多个值.我试图这样做而不导入任何模块.我一直在使用基本的str方法,列表方法和dict方法.
对于txt像这样的文件
453 Sperving_Bearing 9900
1342 Panametric_Fan 23400
9480 Converter_Exchange 93859
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你可以这样做
>>> newDict = {}
>>> with open('testFile.txt', 'r') as f:
for line in f:
splitLine = line.split()
newDict[int(splitLine[0])] = ",".join(splitLine[1:])
>>> newDict
{9480: 'Converter_Exchange,93859', 453: 'Sperving_Bearing,9900', 1342: 'Panametric_Fan,23400'}
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你可以----...通过检查是否删除该行line.startswith('-----').
编辑 - 如果您确定前两行包含相同的内容,那么您可以这样做
>>> testDict = {"Part no.": "Description,Price"}
>>> with open('testFile.txt', 'r') as f:
_ = next(f)
_ = next(f)
for line in f:
splitLine = line.split()
testDict[int(splitLine[0])] = ",".join(splitLine[1:])
>>> testDict
{9480: 'Converter_Exchange,93859', 'Part no.': 'Description,Price', 453: 'Sperving_Bearing,9900', 1342: 'Panametric_Fan,23400'}
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这会testDict在代码中添加第一行并跳过前两行,然后继续正常运行.