使用JSON.NET反序列化值为字段名称的JSON

Question

我有一个非常不受欢迎的情况,需要我反序列化JSON,其中值是JSON.NET的字段名称.假设我有以下JSON,结构非常合理:

{
    "name": "tugberk",
    "roles": [
        { "id": "1", "name": "admin" },
        { "id": "2", "name": "guest" }
    ]
}

使用JSON.NET将其反序列化为CLR对象非常容易:

class Program
{
    static void Main(string[] args)
    {
        var camelCaseSettings = new JsonSerializerSettings { ContractResolver = new CamelCasePropertyNamesContractResolver() };

        var text = File.ReadAllText("user_normal.txt");
        var obj = JsonConvert.DeserializeObject<User>(text, camelCaseSettings);
    }
}

public class User
{
    public string Name { get; set; }
    public Role[] Roles { get; set; }
}

public class Role
{
    public int Id { get; set; }
    public string Name { get; set; }
}

但是,在我目前的情况下,我有以下可怕的JSON,它在值方面相当于以上JSON:

{
    "name": "tugberk",
    "roles": {
        "1": { "name": "admin" },
        "2": { "name": "guest" }
    }
}

如您所见,roles字段不是数组; 它是一个包含其他值作为对象的对象,它的唯一键是它们的字段名称(这很糟糕).User使用JSON.NET 将此JSON反序列化到上面的类的最佳方法是什么？

Answer 1

您可以创建JsonConverter序列化/反序列化的自定义Role[].然后,您可以使用以下方式装饰您的Roles房产JsonConverterAttribute:

public class User
{
    public string Name { get; set; }
    [JsonConverter(typeof(RolesConverter))]
    public Role[] Roles { get; set; }
}

在转换器类中,您可以读取对象并返回数组.您的转换器类可能如下所示:

class RolesConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(Role[]);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        // deserialize as object
        var roles = serializer.Deserialize<JObject>(reader);
        var result = new List<Role>();

        // create an array out of the properties
        foreach (JProperty property in roles.Properties())
        {
            var role = property.Value.ToObject<Role>();
            role.Id = int.Parse(property.Name);
            result.Add(role);
        }

        return result.ToArray();
    }


    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}