如何在Java中解析或拆分URL地址？

Question

如果我有网址.

https://graph.facebook.com/me/home?limit=25&since=1374196005

我可以得到(或拆分)参数(避免硬编码)吗？

像这样

https /// graph.facebook.com /// me/home /// {limit = 25,sincse = 1374196005}

Answer 1

使用Android的Uri课程. http://developer.android.com/reference/android/net/Uri.html

Uri uri = Uri.parse("https://graph.facebook.com/me/home?limit=25&since=1374196005");
String protocol = uri.getScheme();
String server = uri.getAuthority();
String path = uri.getPath();
Set<String> args = uri.getQueryParameterNames();
String limit = uri.getQueryParameter("limit");