Roy*_*mir 2 sql-server ssms crud sql-server-2008
我有这个工具(SSMS工具包),它为特定的表生成CRUD sp
但我看看"插入"代码
/*1*/ CREATE PROC [dbo].[usp_EServices_ME_Country_InfoInsert]
/*2*/ @MasterEntityID int,
/*3*/ ...
/*4*/ AS
/*5*/ SET NOCOUNT ON
/*6*/ SET XACT_ABORT ON
/*7*/
/*8*/ BEGIN TRAN
/*9*/
/*10*/ INSERT INTO [dbo].[EServices_ME_Country_Info] ([MasterEntityID],...)
/*11*/ SELECT @MasterEntityID, ...
/*12*/
/*13*/ -- Begin Return Select <- do not remove
/*14*/ SELECT [ID], [MasterEntityID],...
/*15*/ FROM [dbo].[EServices_ME_Country_Info]
/*16*/ WHERE [ID] = SCOPE_IDENTITY()
/*17*/ -- End Return Select <- do not remove
/*18*/
/*19*/ COMMIT
/*20*/ GO
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我的问题是关于第14行 - 他们/我可以使用output关键字吗?如果是这样,它output会返回所有插入的记录吗?(如果第11行插入的记录> 1)
有趣的问题!根据这里的OUTPUT条款信息,我认为你可以改变这个:
INSERT INTO [dbo].[EServices_ME_Country_Info] ([MasterEntityID],...)
SELECT @MasterEntityID, ...
-- Begin Return Select <- do not remove
SELECT [ID], [MasterEntityID],...
FROM [dbo].[EServices_ME_Country_Info]
WHERE [ID] = SCOPE_IDENTITY()
-- End Return Select <- do not remove
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对此:
INSERT INTO [dbo].[EServices_ME_Country_Info] ([MasterEntityID],...)
OUTPUT INSERTED.MasterEntityID, ...
SELECT @MasterEntityID, ...
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结果相同.这只是现在的理论,我将对此进行测试并跟进.
跟进:
我的OUTPUT条款不正确,你必须OUTPUT在INSERT条款之后使用.在上面的查询中编辑过.我使用以下代码来测试这个:
-- Create a test table
CREATE TABLE TestTable (
ID INT IDENTITY
,TestV1 INT
,TestV2 INT
,TestV3 INT
);
GO
-- Example sp with the 'old' method using SCOPE_IDENTITY()
CREATE PROCEDURE usp_InsertFirstMethod
(
@v1 INT
,@v2 INT
,@v3 INT
)
AS
SET NOCOUNT ON
SET XACT_ABORT ON
BEGIN TRAN
INSERT INTO dbo.TestTable (TestV1, TestV2, TestV3)
SELECT @v1, @v2, @v3;
-- Begin Return Select <- do not remove
SELECT ID, TestV1, TestV2, TestV3
FROM dbo.TestTable
WHERE ID = SCOPE_IDENTITY()
-- End Return Select <- do not remove
COMMIT TRAN;
GO
-- Example sp to show use of OUTPUT clause
CREATE PROCEDURE usp_InsertSecondMethod
(
@v1 INT
,@v2 INT
,@v3 INT
)
AS
SET NOCOUNT ON
SET XACT_ABORT ON
BEGIN TRAN
INSERT INTO dbo.TestTable (TestV1, TestV2, TestV3)
OUTPUT INSERTED.*
SELECT @v1, @v2, @v3;
COMMIT TRAN;
GO
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两者EXECUTE dbo.usp_InsertFirstMethod 1, 2, 3;并EXECUTE dbo.usp_InsertSecondMethod 1, 2, 3;显示相同的结果.似乎工作!