D. *_*. L 6 oracle split multiple-columns
我有一个可以容纳120个字符的地址字段,需要将它分成三个不同的列,每个字符长40个字符.
例:
Table name: Address
Column name: Street_Address
Select Street_Address * from Address
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输出:
123 Main St North Pole Factory 44, near the rear entrance cross the street and turn left and keep walking straight.
我需要将此地址拆分为address_1
address_2
和address_3.
所有三个地址都是varchar(40)数据类型.
所以结果应该是这样的:
Address_1
152 Main st North Pole Factory 44, near
Address_2
the rear entrance cross the street and
Address_3
turn left and keep walking straight.
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请注意,每个地址字段最多可以包含40个字符,并且必须是整个字,它不能被截断一半而且没有意义.
我正在使用oracle 11i数据库.
这相当“快速而肮脏”,但我认为它给出了正确的结果。
我使用了管道表,但可能没有它也可以完成......
create table t1(id number, adr varchar2(120))
/
insert into t1 values(1, '152 Main st North Pole Factory 44, near the rear entrance cross the street and turn left and keep walking straight.')
/
insert into t1 values(2, '122 Main st Pole Factory 44, near the rear entrance cross the street and turn left and keep walking straight. asdsa')
/
create or replace type t is object(id number, phrase1 varchar2(40), phrase2 varchar2(40), phrase3 varchar2(40))
/
create or replace type t_tab as table of t
/
create or replace function split_string(id number, str in varchar2) return t_tab
pipelined is
v_token varchar2(40);
v_token_i number := 0;
v_cur_len number := 0;
v_res_str varchar2(121) := str || ' ';
v_p1 varchar2(40);
v_p2 varchar2(40);
v_p3 varchar2(40);
v_p_i number := 1;
begin
v_token_i := instr(v_res_str, ' ');
while v_token_i > 0 loop
v_token := substr(v_res_str, 1, v_token_i - 1);
if v_cur_len + length(v_token) < 40 then
if v_p_i = 1 then
v_p1 := v_p1 || ' ' || v_token;
elsif v_p_i = 2 then
v_p2 := v_p2 || ' ' || v_token;
elsif v_p_i = 3 then
v_p3 := v_p3 || ' ' || v_token;
end if;
v_cur_len := v_cur_len + length(v_token) +1;
else
v_p_i := v_p_i + 1;
if v_p_i = 2 then
v_p2 := v_p2 || ' ' || v_token;
elsif v_p_i = 3 then
v_p3 := v_p3 || ' ' || v_token;
end if;
v_cur_len := length(v_token);
end if;
v_res_str := substr(v_res_str, v_token_i + 1);
v_token_i := instr(v_res_str, ' ');
end loop;
pipe row(t(id, v_p1, v_p2, v_p3));
return;
end split_string;
/
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和查询:
select parts.*, length(PHRASE1), length(PHRASE2), length(PHRASE3)
from t1, table(split_string(t1.id, t1.adr)) parts
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