Kri*_*nie 5 c++ boost-spirit wavefront boost-spirit-qi
我想以递归方式解析字符串并将结果存储在一个结构中.我编写了一个可以处理一次迭代的解析器.输入格式如下:
v 1.5 2.0 2.5
v 3.0 3.5 4.0
f 1 2 3
f 4 5 6
v 4.5 5.0 5.5
v 6.0 6.5 7.0
f 7 8 9
f 10 11 12
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问题是它只解析前4行,它在第三行遇到'v'时停止.完整的代码如下.如何修改此代码,以便将其余输入解析为同一个结构?我已经尝试将启动规则修改start = vertex >> elements为start = *(vertex >> elements),但这只会产生巨大的编译错误.同样如此start = +(vertex >> elements).有什么想法我应该如何修改规则?
#include <iostream>
#include <sstream>
#include <fstream>
#include "boost/spirit/include/qi.hpp"
#include "boost/spirit/include/support_iso8859_1.hpp"
#include "boost/fusion/include/adapt_struct.hpp"
struct ElemParseData
{
std::vector<float> verts;
std::vector<unsigned int> idx;
};
BOOST_FUSION_ADAPT_STRUCT(
ElemParseData,
(std::vector<float>, verts)
(std::vector<unsigned int>, idx)
)
bool doParse( ElemParseData &parseData, const std::string &data )
{
namespace qi = boost::spirit::qi;
namespace iso8859 = boost::spirit::iso8859_1;
struct objGram : qi::grammar<std::string::const_iterator, ElemParseData(), iso8859::space_type>
{
objGram() : objGram::base_type(start)
{
vertex = *('v' >> qi::double_ >> qi::double_ >> qi::double_);
elements = *('f' >> qi::int_ >> qi::int_ >> qi::int_);
start = vertex >> elements;
}
qi::rule<std::string::const_iterator, ElemParseData(), iso8859::space_type> start;
qi::rule<std::string::const_iterator, std::vector<float>(), iso8859::space_type> vertex;
qi::rule<std::string::const_iterator, std::vector<unsigned int>(), iso8859::space_type> elements;
} objGrammar;
std::string::const_iterator f = data.cbegin();
bool res = qi::phrase_parse( f, data.cend(), objGrammar, iso8859::space, parseData );
// print everything that hasn't been processed by the parser
std::cout << "#### Trail ####" << std::endl;
std::cout << std::string(f, data.cend()) << std::endl;
return res;
}
int main( int argc, char* argv[] )
{
std::stringstream ss;
std::filebuf fb;
if ( fb.open("parsetest.txt", std::ios::in) )
{
std::istream is(&fb);
while (is)
ss << char(is.get());
fb.close();
}
ElemParseData parseData;
bool res = doParse( parseData, ss.str() );
// print results
std::cout << std::endl << "Parsing result: " << res << std::endl;
std::cout << "---######### ResultData #########---" << std::endl;
std::cout << "---- Begin vertex data ----" << std::endl;
std::vector<float>::iterator it;
for ( it = parseData.verts.begin(); it != parseData.verts.end(); ++it )
std::cout << *it << std::endl;
std::cout << "---- End vertex data ----" << std::endl;
std::cout << std::endl;
std::cout << "---- Begin index data ----" << std::endl;
std::vector<unsigned int>::iterator idxIt;
for ( idxIt = parseData.idx.begin(); idxIt != parseData.idx.end(); ++idxIt )
std::cout << *idxIt << std::endl;
std::cout << "---- End index data ----" << std::endl;
std::cout << "Press enter to exit" << std::endl;
std::cin.get();
}
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PS:如果需要,可以在此处找到编译错误.
编辑:我正在尝试编写一个Wavefront .OBJ解析器.这里给出的输入只是我的问题的简化.
seh*_*ehe 11
有几种方法:)
最干净的,IMO将BOOST_FUSION_ADAPT_STRUCT通过Spirit的自定义容器属性特征替换Fusion Sequence Adaptation():
namespace boost { namespace spirit { namespace traits {
template<>
struct is_container<ElemParseData, void> : mpl::true_ { };
template<>
struct container_value<ElemParseData, void> {
typedef boost::variant<float, unsigned int> type;
};
template <>
struct push_back_container<ElemParseData, std::vector<float>, void> {
static bool call(ElemParseData& c, std::vector<float> const& val) {
c.verts.insert(c.verts.end(), val.begin(), val.end());
return true;
}
};
template <>
struct push_back_container<ElemParseData, std::vector<unsigned int>, void> {
static bool call(ElemParseData& c, std::vector<unsigned int> const& val) {
c.idx.insert(c.idx.end(), val.begin(), val.end());
return true;
}
};
}}}
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如果不改变语法,这只会产生相同的效果.但是,现在您可以修改解析器以期望所需的语法:
vertex = 'v' >> qi::double_ >> qi::double_ >> qi::double_;
elements = 'f' >> qi::int_ >> qi::int_ >> qi::int_;
start = *(vertex | elements);
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由于这些特质,Spirit将"只知道"如何插入ElemParseData.在Coliru上看到它
您可以在语义操作中连接它:
start = *(
vertex [phx::bind(insert, _val, _1)]
| elements [phx::bind(insert, _val, _1)]
);
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使用insert类型的成员inserter:
struct inserter {
template <typename,typename> struct result { typedef void type; };
template <typename Attr, typename Vec>
void operator()(Attr& attr, Vec const& v) const { dispatch(attr, v); }
private:
static void dispatch(ElemParseData& data, std::vector<float> vertices) {
data.verts.insert(data.verts.end(), vertices.begin(), vertices.end());
}
static void dispatch(ElemParseData& data, std::vector<unsigned int> indices) {
data.idx.insert(data.idx.end(), indices.begin(), indices.end());
}
};
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这看起来大致相同,它也是如此:住在Coliru
这是唯一不需要任何管道的解决方案,除非包括boost/spirit/include/phoenix.hpp:
struct objGram : qi::grammar<std::string::const_iterator, ElemParseData(), iso8859::space_type>
{
objGram() : objGram::base_type(start)
{
using namespace qi;
auto add_vertex = phx::push_back(phx::bind(&ElemParseData::verts, _r1), _1);
auto add_index = phx::push_back(phx::bind(&ElemParseData::idx, _r1), _1);
vertex = 'v' >> double_ [add_vertex] >> double_ [add_vertex] >> double_ [add_vertex];
elements = 'f' >> int_ [add_index] >> int_ [add_index] >> int_ [add_index] ;
start = *(vertex(_val) | elements(_val));
}
qi::rule<std::string::const_iterator, ElemParseData(), iso8859::space_type> start;
qi::rule<std::string::const_iterator, void(ElemParseData&), iso8859::space_type> vertex, elements;
} objGrammar;
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注意:
ElemParseData不可撤销地推入成员中).边注
read循环中有一个错误,更喜欢更简单的选项:
Run Code Online (Sandbox Code Playgroud)std::filebuf fb; if (fb.open("parsetest.txt", std::ios::in)) { ss << &fb; fb.close(); }或考虑一下
boost::spirit::istream_iterator
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