Jos*_*ant 9 c# string string-concatenation compile-time
C#是否对常量字符串连接进行任何编译时优化?如果是这样,我的代码如何通过编写来利用这个?
示例:这些在运行时如何比较?
Console.WriteLine("ABC" + "DEF");
const string s1 = "ABC";
Console.WriteLine(s1 + "DEF");
const string s1 = "ABC";
const string s2 = s1 + "DEF";
Console.WriteLine(s2);
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jas*_*son 15
是的,它确实.您可以使用ildasm或Reflector来检查代码来验证这一点.
static void Main(string[] args) {
string s = "A" + "B";
Console.WriteLine(s);
}
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被翻译成
.method private hidebysig static void Main(string[] args) cil managed {
.entrypoint
// Code size 17 (0x11)
.maxstack 1
.locals init ([0] string s)
IL_0000: nop
IL_0001: ldstr "AB" // note that "A" + "B" is concatenated to "AB"
IL_0006: stloc.0
IL_0007: ldloc.0
IL_0008: call void [mscorlib]System.Console::WriteLine(string)
IL_000d: nop
IL_000e: br.s IL_0010
IL_0010: ret
} // end of method Program::Main
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有一些更有趣但有相关的事情发生.如果程序集中有字符串文字,则CLR将仅为程序集中同一文字的所有实例创建一个对象.
从而:
static void Main(string[] args) {
string s = "A" + "B";
string t = "A" + "B";
Console.WriteLine(Object.ReferenceEquals(s, t)); // prints true!
}
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将在控制台上打印"True"!此优化称为字符串实习.
根据Reflector:
Console.WriteLine("ABCDEF");
Console.WriteLine("ABCDEF");
Console.WriteLine("ABCDEF");
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即使在Debug配置中也是如此.
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