确定用户输入中最常见的单词.[蟒蛇]

Question

我尝试解决此问题的方法是将用户的单词输入到列表中,然后使用.count()查看单词在列表中的次数.问题是每当出现平局时,我需要打印所有出现次数最多的单词.只有当我使用的单词不在另一个出现相同次数的单词内时,它才有效.例如:如果我按顺序使用吉米和吉姆,它只会打印吉米.

for value in usrinput:
        dict.append(value)
    for val in range(len(dict)):
        count = dict.count(dict[val])
        print(dict[val],count)

        if (count > max):
            max = count
            common= dict[val]
        elif(count == max):
            if(dict[val] in common):
                pass
            else:
                common+= "| " + dict[val]

Answer 1

使用collections.Counter课程.我会给你一个提示.

>>> from collections import Counter
>>> a = Counter()
>>> a['word'] += 1
>>> a['word'] += 1
>>> a['test'] += 1
>>> a.most_common()
[('word', 2), ('test', 1)]

您可以从此处提取单词和频率.

使用它从用户输入中提取频率.

>>> userInput = raw_input("Enter Something: ")
Enter Something: abc def ghi abc abc abc ghi
>>> testDict = Counter(userInput.split(" "))
>>> testDict.most_common()
[('abc', 4), ('ghi', 2), ('def', 1)]