Dav*_*sky 20 delphi constructor overloading
我正在尝试创建一个子类的TForm
这是我现在的代码:
interface
TfrmEndoscopistSearch = class(TForm)
public
/// original constructor kept for compatibility
constructor Create(AOwner : TComponent); overload; override;
/// additional constructor allows for a caller-defined base data set
constructor Create(AOwner : TComponent; ADataSet : TDataSet; ACaption : string = ''); overload;
end;
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它似乎工作,但我总是得到编译器警告:
[Warning] test.pas(44): Method 'Create' hides virtual method of base type 'TCustomForm'
Rob*_*edy 31
有一种非常简单的方法可以避免这种情况.为新构造函数指定一个不同的名称.与其他一些流行语言不同,Delphi 命名了构造函数 ; 你不必称他们为Create.您可以调用新的CreateWithDataset,而不是干扰虚拟的Create构造函数.
TfrmEndoscopistSearch = class(TForm)
/// original constructor kept for compatibility
constructor Create(AOwner: TComponent); override;
/// additional constructor allows for a caller-defined base data set
constructor CreateWithDataset(AOwner: TComponent; ADataSet: TDataSet; ACaption: string = '');
end;
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实际上,除非您以多态方式实例化此类,否则您甚至不需要原始构造函数.你可以像这样申报新的:
TfrmEndoscopistSearch = class(TForm)
/// additional constructor allows for a caller-defined base data set
constructor Create(AOwner: TComponent; ADataSet: TDataSet; ACaption: string = ''); reintroduce;
end;
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试图直接在TfrmEndoscopistSearch上调用单参数构造函数会产生编译错误.
(以多态方式创建它通常涉及使用Application.CreateForm:
Application.CreateForm(TfrmEndoscopistSearch, frmEndoscopistSearch);
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这总是调用TComponent中引入的单参数虚拟构造函数.除非它是您的主要形式,否则您不需要这样做.我以前写过关于Application.CreateForm的感受.)
Uli*_*rdt 19
尝试reintroduce在第二个之前添加overload,如下所示:
TfrmEndoscopistSearch = class(TForm)
public
/// original constructor kept for compatibility
constructor Create(AOwner : TComponent); overload; override;
/// additional constructor allows for a caller-defined base data set
constructor Create(AOwner : TComponent; ADataSet : TDataSet; ACaption : string = ''); reintroduce; overload;
end;
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这在Turbo Delphi中编译.我需要public让它编译,因为published方法的重载受到限制.
constructor Create(AOwner:Tcomponent;str:string);overload;
...
constructor TfrmEndoscopistSearch.Create(AOwner: Tcomponent; str: string);
begin
inherited Create(AOwner);
showmessage(str);
end;
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这应该可以解决问题